Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
Answer:
measure of a angle 1 = x
measure of angle 2= 3x
3x+1x=180 ( linear pair)
4x=180
x= 180÷4
x= 45
angle one = x= 45
angle two = 3x = 3×45= 135
the 2 angles are
45 and 135
Answer:
A. baseball field
Step-by-step explanation:
Answer:
5x + 9
Step-by-step explanation:
f(x) = 3x+4
g(x) = 2x + 5
(f+g)(x)
(3x+4) + (2x + 5)
= 5x + 9
// however I'm unsure
Answer:
11 units
Step-by-step explanation:
According to ruler postulate, if there are two points A with coordinate a
and point B with coordinate b, \
then distance ab is given by subtracting coordinate in any order i.e it can be (a-b) or (b-a) and then take the absolute value value of it.
mathematically it can be represented as
AB = |a-b| or |b-a|
_________________________________________
in the given problem points are -9 and 2
thus distance
distance between –9 and 2 = |-9 -2| = |-11| = 11
absolute value of -11 is 11
alternatively, distance can be calculated as
distance between –9 and 2 = |2 -(-9) | = |2 + 9 | = |-11| = 11
