Answer:
Rectangle
Step-by-step explanation:
Note the definition of a rectangle. All angles must be 90°, and opposite sides are parallel and congruent.
It says that Andre "drew a quadrilateral with <em>four right angles and two pairs of congruent sides</em>.", making rectangle a candidate as an answer.
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Answer:
Function B has the greater initial value because the initial value for function A is 4 and the initial value for Function B is 5
Step-by-step explanation:
- <em>The initial value of a function is the output value of the function when the input value is 0</em>
Initial value of A is y=4 at x=0,
and
initial value of B is y=0*6+5= 5 at x=0
Function B has the greater initial value because the initial value for function A is 4 and the initial value for Function B is 5
Answer:
3) 27 cubed
4) 72 cubed
5) 125 cubed
8) 27 cubed. 3 is the length, 3 is the width, and 3 is the height.
9) 72 cubed. 6 is the length, 3 is the width, and 4 is the height.
10) 125 cubed. 5 is the length, 5 is the width, and 5 is the height.
Step-by-step explanation
Here's what to show if your teacher requires for you to show your work.
3) 3 x 3 x 3 = 27
4) 6 x 3 x 4 = 72
5) 5 x 5 x 5 = 125
8) 3 x 3 x 3 = 27
9) 6 x 3 x 4 = 72
10) 5 x 5 x 5 = 125
These are the ones I'd suggest putting the up and down form on.
10) and 5) Also put 5 x 5 = 25. 4) and 9) Also put 6 x 3 = 18.
<em>2 3</em>
25 18
<u>x 5 </u> <u>x 4 </u>
125 72
Hoped this answered everything! Feel free to ask me if there's something I missed! :)
2.5 kilograms in grams is 2500 grams.
2.5kg = 2500g
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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