Problem 7
This triangle is an equilateral triangle. All sides are the same length (some unknown number which we don't care about). All angles are the same measure each 60 degrees. Set this expression equal to 60 and solve for x
25x - 15 = 60
25x - 15+15 = 60+15 ... add 15 to both sides
25x = 75
25x/25 = 75/25 .... divide both sides by 25
x = 3 which is the answer we want
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Problem 8
For this problem, I've decided to break up the work into separate image files to show how I did the steps. Otherwise, it might be really cluttered to have everything typed here on the same page.
To get the coordinates of point E, check out the image labeled "figure 1". For point G, look at "figure 2".
For proof that EG is parallel to BC, look at "figure 3"
For proof that segment EG is half the length of segment BC, look at "figure 4"
Finally, I've drawn on the diagram to visually show what it all looks like as a summary in "figure 5"
The graphs of two linear equations cannot intersect in two different points. the correct answer is B.

Compare to the vertex form of parabola
So vertex should be at (h,k)=(-2,-1)
Graph attached
Answer:
<h2><em><u>448</u></em><em><u> </u></em><em><u>sq.ft</u></em></h2>
Step-by-step explanation:
The following figure is a <em><u>trapezium</u></em><em><u>, </u></em>
<em><u>So</u></em><em><u> </u></em><em><u>Given</u></em><em><u>,</u></em>
Parallel sides of the trapezium = 17ft and 39ft
Height of the trapezium = 16ft
<em><u>Therefore</u></em><em><u>, </u></em>
Area of the trapezium





<em><u>Hence</u></em><em><u>,</u></em>
<em><u>448</u></em><em><u> </u></em><em><u>sq.ft</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>trapezium</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
Answer: 20
Step-by-step explanation: how i got the answer was to multiply everything by two. then add everything together.