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3 years ago

Solve for x in the equation 2x2-5x+1=3

1 answer:

5 0

2x^2 - 5x + 1 = 3

Subtract 3 from both sides
2x^2 - 5x + 1 - 3 = 3 - 3

2x^2 - 5x - 2 = 0

Use quadratic formula with A = 2, B = - 5, C = - 2

x = - b +- sqrt b^2 - 4ac/2a

x = - ( - 5) +- sqrt (- 5)^2 - 4(2)( - 2)/(2)(2)

x = 5 +- sqrt 41/4

x = 5/4 + 1/4sqrt 41 or x = 5/4 + - 1/4 sqrt 41

Answer: x = 5/4 + 1/4 sqrt 41
x = 5/4 + - 1/4 sqrt 41

Hope that helps!!!!! (D)

You might be interested in

8x^3y^2______+3xy^2-4y^3

user100 [1]

Answer:

what is the equation clearly mention it first u r giving that power 8x is 3y and then u r telling the power 3y only wah what a question plz mention ur question properly

7 0

3 years ago

What is the area, in square centimeters, of a circle that is 8 centimeters

Shalnov [3]

Answer: 8=201.06

4=50.27

Step-by-step explanation: What I mean by this is that if the radius (the distance from the center of the circle to the edge of the circle ) is 8 then the area of the circle is 201.06 and if the radius of the circle is 4 then the area of the circle is 50.27

5 0

3 years ago

Need help with this??? Please!!!

Radda [10]

Answer:

the first option

Step-by-step explanation:

(f-g)(x) simply means to subtract both expressions. really literally.

and we go through it power by power of x.

the highest power/exponent of x is 3 (x³). only f(x) has one.

so, -7x³ is the first part of f-g.

next is x².

11x² - 6x² = 5x², which is the second part of f-g.

next is x.

-8x - (-14x) = -8x + 14x = 6x, which is the third part of f-g.

next is x⁰ (in other words, no x, just a constant).

4 - (-3) = 4 + 3 = 7, which is the 4th part of f-g.

we have no x to the power of -1 or -2, so we have -3

0 - (-4x‐³) = 4x‐³, which is the last part of f-g.

so, it is clearly the first answer option.

3 0

2 years ago

Help people’s please

marishachu [46]

Answer:

Step-by-step explanation:

6+6=12

12+12=24

24+24=48

and

48+48=96

8 0

3 years ago

Read 2 more answers

Find the error in the following sample of work, if one exists.

ch4aika [34]

Answer:

D. There is no mistake.

Step-by-step explanation:

The following lines show the process of factorization by using common factor.

Line 1:

In line 1, the equation is given and is completely fine.

$y^{2}+8xy+2y+16x=0$

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.

Line 2:

In line 2, the terms are grouped, from which we can factor out common terms.

$(y^{2}+8xy)+(2y+16x)=0$

This is also fine.

Line 3:

In line 3, the common term y is taken out from group 1 and 2 from other group.

$y(y+8x)+2(y+8x)=0$

which is exactly what is given in line 3.

Line 4:

In line 4 the common factors can be seen and easily split into 2 factors.

$(y+2)(y+8x)=0$

which is exactly what is given in line 4.

Options:

A. The grouping is correct in line 2. So this option is does not hold.

B. Common factor was factored correctly from group 1. So this option does not hold.

C. Common factor was factored correctly from group 2. So this option does not hold.

D. There is no mistake. This is correct. Thus we choose this option as correct answer.

3 0

3 years ago