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3 years ago

What are two partial products you could add to find 990 x 37 ?

1 answer:

7 0

Answer:

Method 2:

⇒(1,000-10)×(30+7)
=1,000×(30+7)-10×(30+7)
=30,000+7,000-300-70
=37,000-370
=36,630

Method 1:

990×(40-3)
=990×40-990×3
=39,600 -2970
=36,630

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You are a librarian. You know that approximately 12% of books that are checked out get returned late. Each late book results in

Akimi4 [234]

Answer:

A shows the correct set of equation.

Late books = 12/100 x 462

Total fines = late books/4.25

Step-by-step explanation:

Total number of books issued = 462

Fine on late books = $4.25 per book

12% of the issued books are late returned.

So, the number of the books that are returned late here= 12% of 462

Late books = $\frac{12}{100} \times 462$

Also, Since fine on each late book = $4.62

The fine on late books = Total number of late books x ($4. 62)

So, A. is the correct option

8 0

3 years ago

Show all of your work, even though the question may not explicitly remind you to do so. Clearly label any functions, graphs, tab

natta225 [31]

Answer:

(a) at t=2, the particle is moving toward the origin

(b) a(t) = 70(8 -9t^2)/(3t^2 +8)^3; a(2) = -0.245

Step-by-step explanation:

(a) The function x(t) is negative for -3 < t < 3, so at t = 2, the particle is to the left of the origin.

The velocity of the particle is given by the derivative of the position function:

$x'(t)=\dfrac{(3t^2+8)(2t)-(t^2-9)(6t)}{(3t^2+8)^2}=\dfrac{70t}{(3t^2+8)^2}$

Then, at t=2, the expression is positive, indicating the particle is moving toward the origin.

(b) The acceleration is the derivative of the velocity, so is ...

$a(t)=\dfrac{70(3t^2+8)^2-(70t)(12t)(3t^2+8)}{(3t^2+8)^4}=\dfrac{70(3t^2+8-12t^2)}{(3t^2+8)^3}\\\\\boxed{a(t)=\dfrac{70(8-9t^2)}{(3t^2+8)^3}}$

Then at t=2, the acceleration is ...

a(2) = 70(8 -9·4)/(3·4+8)^3 = 70(-28)/8000

a(2) = -0.245

(c) As t gets large, the value of x(t) approaches t^2/(3t^2) = 1/3.

7 0

4 years ago

How do I solve this?

vampirchik [111]

4 , divide the x by the y to find a constant

4 0

3 years ago

Paul tosses a quarter off the Main Street bridge into the St. John’s River. The

IRINA_888 [86]

C because maximum height of a quarter

4 0

3 years ago

PLEASE HELP TY<br> show all work

aksik [14]

Answer:

36 cm

Step-by-step explanation:

$V= \frac{4}{3} \pi r^{3}$

$3V= 4\pi r^{3}$

$r^{3}=\frac{3V}{4\pi }$

$r= 3\sqrt{\frac{3V}{4\pi } }$

$r=3\sqrt{\frac{3* 24429 cm^{3} }{4\pi } }$

r=18 cm

diameter= d= 2r

d= 2(18cm)= 36 cm

5 0

4 years ago