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stepan [7]
3 years ago
14

What are two partial products you could add to find 990 x 37 ?

Mathematics
1 answer:
kap26 [50]3 years ago
7 0
Answer:

Method 2:

⇒(1,000-10)×(30+7)
=1,000×(30+7)-10×(30+7)
=30,000+7,000-300-70
=37,000-370
=36,630

Method 1:

990×(40-3)
=990×40-990×3
=39,600 -2970
=36,630
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Solve system of linear equation by substitution -x+y=2; 3x-5y=-4
GarryVolchara [31]

Answer:

(-3,-1)

Step-by-step explanation:

-x+y=2

3x-5y=-4

in the top equation, we can get y by itself on one side of the equation:

-x+y=2

y=x+2

now, since we know that y=x+2, in the bottom equation we can substitute x+2 for y (substitution method) and solve:

3x-5y=-4

3x-5(x+2)=-4

3x-5x-10=-4

-2x-10=-4

-2x=6

x=-3

since we now know that x=-3, we can use it to find y by plugging in -3 for x in the top equation (you can do it in either equation, but doing it in the top equation is easier):

y=x+2

y=-3+2

y=-1

answer: (-3, -1)

7 0
3 years ago
Using Pythagorean Theorem what is the square root of the third side ?
IrinaVladis [17]
Pythagorean theorm is a^2+b^2=c^2
so 10^2+ 24^2 =c^2
100+576=c^2
676=c^2
26=c
5 0
3 years ago
A 2 liter drink costs $0.15 per deciliter. How much will the drink cost?
miv72 [106K]
The drink costs $3.00
7 0
4 years ago
Read 2 more answers
What is the distance between point A and point B?
artcher [175]

Answer:

I would need to see the grapgh

Step-by-step explanation:

4 0
3 years ago
A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
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