Answer:
a is the right answer I calculated it
The two-way table is attached.
We know that 63 people took the survey, and 22 of them were left-handed. This means that 63-22=41 of them are right handed.
Out of the 63 total, 37 are left brain dominant; this means that 63-37=26 are right brain dominant.
Of the 26 that are right brain dominant, 21 are right handed; this means 26-21=5 are left handed.
Of the 22 left-handed people, 5 are right brain dominant; this means 22-5 = 17 are left brain dominant.
Of the 37 left brain dominant people, 17 are left handed; this means 37-17=20 are right handed.
R(x)= -x2+3x is x=0
s(x)= 2x+1 is x= -1 over 2
(-1-2) (0)
Since the Σ( of all colors )= 100%, OR 1, then:
a) P(GREEN ∪ BLUEU) = P(G) + P(BL) = 8%+6% = 14% or 0.14
Since we have to choose ONE candy and only ONE candy at random, then tey are mutually exclusive: No. Choosing a green and blue M&M is possible
b) P(YELLOW ∪ RED) = P(Y) + P(R) = 18%+18% = 36% or 0.36
SAME ANSWER AS BEFORE: mutually exclusive
c) P(NOT PURPLE), Let's calculate 1st, the probability of having a PURPLE:
P(PURPLE) = 21% or 0.21
And the Probability of NOT having a PURPLE is 1-0.21 = 0.79
<span>With a boys to girls ratio of 8:7, this means 8/15 of the campers are boys and 7/15 of the campers are girls.
We are told that there are 195 total campers.
To find # of boys: 195 (the total # of campers) x 8/15 (fraction of the campers that are boys) = 104 boys
To find # of girls: 195 (total # of campers) x 7/15 (fraction of the campers that are girls) = 91 girls
Note: If you do not know how to multiply by fractions, let me know, I have another trick that takes more time but doesn't require the use of fractions.
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