Given B = {a, c, e, g, i, k} and C = {h, i, j, k}, we have
C' = {a, b, c, d, e, f, g}
so that
B U C' = {a, b, c, d, e, f, g, i, k}
and so
n(B U C') = 9
Answer:
Unusual
Step-by-step explanation:
we know that
The z-score is a measure of how close the given data point is to the mean of the values given with the standard deviation
so
if its z-score is greater than or equal to -2, or less than or equal to 2., then the data value is considered ordinary
if its z-score is less than -2 or greater than 2, then the data value is considered unusual
(5x+1)(2x+1)(x+4)
The factored from of a polynomial can be found from the zeros or x-intercepts of the graph.
The x-intercepts here are x= -1/5, x=-1/2 and x= -4. You can find the factors by finding the expression which solves for each value.
Since x = -1/5 then the factor is 5x+1.
Since x = -1/2 then the factor is 2x+1.
Since x = -4 then the factor is x+4.
So the factored form is (5x+1)(2x+1)(x+4).
leading coefficient is 1
degree is 9
Your answer is 71
7+2(n-1)
we have our n as 8
so,7+2(8-1)
9(7)=63
