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Paraphin [41]
3 years ago
5

Write the polynomial equation for -1/5,-1/2,-4​

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

(5x+1)(2x+1)(x+4)

Step-by-step explanation:

The factored from of a polynomial can be found from the zeros or x-intercepts of the graph.

The x-intercepts here are x= -1/5, x=-1/2 and x= -4. You can find the factors by finding the expression which solves for each value.

Since x = -1/5 then the factor is 5x+1.

Since x = -1/2 then the factor is 2x+1.

Since x = -4 then the factor is x+4.

So the factored form is (5x+1)(2x+1)(x+4).

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Sara reads 250 words per minute for 2 hours and gets tired and reads 125 words per minute for 3 hours. on average how many words
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125*(3*60)=22500
22500+30000=52500
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4 years ago
Erin has a balance of $1,150.34 in her check register. On her statement, the balance of her account is $844.93. Not reported on
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Step-by-step explanation:

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3 years ago
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

DG=AG-AD=9-7=2\ units

substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0
3 years ago
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