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PilotLPTM [1.2K]
2 years ago
6

You have 132 m of fencing with which to make 2 side by side rectangular enclosures against an existing wall. If the enclosures a

re adjacent and of the same depth, what is the maximum area that can be enclosed
Please answer ASAP will give out brainiest
Mathematics
1 answer:
Deffense [45]2 years ago
8 0
The two enclosures will need three equal fences coming out from the wall and meeting another fence running parallel to the wall. If the fences coming out from the wall are x metres long the parallel fence will be (132 - 3x) metres long.
The area A = x(132 - 3x) = 132x - 3x^2
The derivative of A = zero when 132 - 6x = 0 which means the maximum area is when x = 22m
The maximum area = 22 x (132 - 3 x 22) = 1452 m^2

If you don’t know how to find derivatives then you could sketch the graph of y = x(132 - 3x).
This is an inverted parabola (hill) with x intercepts at 0 and 132/3 = 44.
The maximum point (top of the hill) is halfway between 0 and 44 I.e. 22m

Try any other value for x and the area will be smaller.
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PLEASE HELP!!
aliya0001 [1]

Ik this is late, but people who are looking for the answer can see this.

Answer:

an =1/3*6^n-1

Step-by-step explanation:

You should plug in 2 for n in each equation, which, the correct one should give you 2. Then, to make sure, you plug in 3 in the equations that gave you 2.

Example:

an = 1/3 * 6 ^n-1

Plug in 2.

an = 1/3 * 6 ^2-1

an = 1/3 * 6 ^1

1/3 * 6 = 2

Step 2.

an = 1/3 * 6 ^3-1

an = 1/3 * 6 ^2

1/3 * 36 = 12

Hope this helps.

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3 years ago
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3 years ago
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xxTIMURxx [149]

Answer: 45 Degrees

Step-by-step explanation:

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2 years ago
Find the equation of the exponential function represented by the table below:
shusha [124]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
A train leaves Miami at 3:00pm. A second train leaves the same city in the same direction at 5:00pm. The second train travels 50
Alexxandr [17]
Let the speed of the first train be v mph. Then the speed of the second train is:
(v + 50) mph.
Distance traveled by the first train from 3pm to 7pm = 4v miles.
The second train travels 4v miles in 2 hours (from 5pm to 7pm). Therefore the speed of the second train = (4v)/2 = 2v.
However the speed of the second train is also given by (v + 50) mph.
v + 50 = 2v
v = 50.
The speed of the first train is 50 mph and the speed of the second train is 100 mph.
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