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3 years ago

Question 2 please help

Mathematics

2 answers:

photoshop1234 [79]3 years ago

8 0

The mean is the average
so Monday to Friday is 5 days.

98 * 5 = 490 people between Monday and Friday

The mean for 7 days was 114 * 7 = 798 people

798 - 490 = 308 people on Saturday and Sunday

308 - 162 = 146 people on Sunday

slamgirl [31]3 years ago

6 0

I got 124 people visit the gym

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the graph shows your budget and the total cost of x gallons of gasoline and a car wash you want to determine the possible amount

Yuki888 [10]

Answer:

Part a) The budget is $40

Part b) The cost of one gallon of gasoline is $3.55 and the cost of the car wash is $8

Part c) $x \leq 9.01\ gal$

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure

Part a) What is your budget?

The budget is given by the equation

y=40

therefore

The budget is $40

Part b) How much does a gallon of gasoline cost? how much does a car wash cost?

Let

y ------> the cost of a gallon of gasoline plus the cost of a car wash

x -----> the amount of gasoline in gallons

we have

y=3.55x+8

In this problem

For x=0

y=3.55(0)+8=8

The y-intercept is the cost of the car wash

The cost of the car wash is $8

Find the cost of one gallon of gasoline

we know that

The slope of the linear equation is

m=$3.55 per gallon

therefore

The cost of one gallon of gasoline is $3.55

Part c) Write an inequality that represent the possible amounts of gasoline you can buy

we have

$3.55x+8 \leq 40$

Solve for x

$3.55x \leq 40-8$

$3.55x \leq 32$

$x \leq 9.01\ gal$

Part d) Use the graph to estimate the solution of the inequality in part c)

we have the system

y=40

y=3.55x+8

The solution of the system is the intersection point both graphs

Looking at the graph the intersection point is about (9,40)

That means ----> The maximum amount of gasoline you can buy with the budget is about 9 gallons

7 0

2 years ago

Use the triangle below to find cos V.

Semenov [28]

Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

$UV^2 = 261$

Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

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2 years ago

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dimaraw [331]

32, i believe is the answer

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AysviL [449]

Step-by-step explanation:

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