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3 years ago

5

Find the gradient of the line segment between the points (2,-2 and (0,-6

1 answer:

Gwar [14]3 years ago

7 0

Answer:2

Step-by-step explanation:

x1 = 2

y1=-2

x2= 0

y2= -6

Gradient = $\frac{y2 - y1}{x2-x1} \\\\\\\frac{-6- (-2)}{0 - 2} \\\\\frac{-6 + 2}{-2} \\\\\frac{-4}{-2} \\\\Gradient = 2$

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Will give Brainly <br><br> 4827 + 1111 /20

pashok25 [27]

Answer:

4882.55

Step-by-step explanation:

1111/20 = 55.55

55.55 + 4827 = 4882.55

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3 years ago

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At the beach the cost for renting a surf board is 39 dollars for 3 hrs. At this rate that is the charge for 8 hrs.

erma4kov [3.2K]

Answer:

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Step-by-step explanation:

So, in one hour it would cost $13. Times 8, because we want to see what would be the cost for 8 hours, and 8 times 13 is 104.

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3 years ago

IgorLugansk [536]

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Step-by-step explanation:

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3 years ago

Generate the nest three terms of each arithmetic sequence shown below.

o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{2}=a_{1}+(2-1)d$

$a_{2}=a_{1}+(1)d$

Substituting the given value we get

$a_{2}= -2+(1)4$

$a_{2}= -2+4$

$a_{2}= 2$

------------------------------------------

Similarly

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the given value we get

$a_{3}= -2+(2)4$

$a_{3}= -2+8$

$a_{3}= 6$

-------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the given value we get

$a_{4}= -2+(3)4$

$a_{4}= -2+16$

$a_{4}= 10$

-------------------------------------------------------------------------------------------

<u>B</u><u> $a_n=a_{(n-1)}-8$ with $a_1=10$ </u>

$a_2=a_{(2-1)}-8$

$a_2=a_{1}-8$

Substituting the given value

$a_2= 10-8$

$a_2=2$

---------------------------------------------------------------------

$a_3=a_{(3-1)}-8$

$a_3=a_{2}-8$

Substituting the value

$a_3=2-8$

$a_3= -6$

---------------------------------------------------------------------

$a_4=a_{(4-1)}-8$

$a_4=a_{3}-8$

Substituting the value

$a_4= -6-8$

$a_4= -14$

-------------------------------------------------------------------------------------------

<u>C) $a_1=3, a_2=1$ </u>

Here the difference is -2

the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the value we get

$a_{3}= 3+(2)-2$

$a_{3}= 3-4$

$a_{3}= -1$

------------------------------------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the value we get

$a_{4}= 3+(3)-2$

$a_{4}= 3-6$

$a_{4}= -3$

----------------------------------------------------------------------------------

$a_{5}=a_{1}+(5-1)d$

$a_{5}=a_{1}+(4)d$

Substituting the value we get

$a_{5}= 3+(4)-2$

$a_{5}= 3-8$

$a_{5}= -5$

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3 years ago

1400 60% purchased what is the amount purchased

Morgarella [4.7K]

60% of 1400 would be 840, if I am reading the problem correctly

7 0

3 years ago