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2 years ago

Do you think patterns are helpful in creating harmony and order in nature?

Mathematics

2 answers:

Kay [80]2 years ago

6 0

Answer:

Patterns help us organize thoughts and establish order to our lives. As we begin to connect patterns in nature and life, they bring a sense of harmony to our minds. Patterns lead to and build math, vocabulary and cognitive concepts.

hope it help you

yawa3891 [41]2 years ago

4 0

Answer:

Answer:

How do patterns help us?

The ability to recognize and create patterns help us make predictions based on our observations; this is an important skill in math. Understanding patterns help prepare children for learning complex number concepts and mathematical operations. ... Patterns allow us to see relationships and develop generalisations.

hope it's helpful

thank you

You might be interested in

9 x 7 = ( x 7) – (1 x 7)<br> = 70-<br> =

WARRIOR [948]

Answer:

Step-by-step explanation:

9x7=(10x7)-1x(7)

=70-7

=63

8 0

2 years ago

To offset college expenses, at the beginning of your freshman year you obtain a nonsubsidized student loan for $15,000. Interest

soldier1979 [14.2K]

Answer:

15000(1.003425)^12t ;

4.11%

4.188%

Step-by-step explanation:

Given that:

Loan amount = principal = $15000

Interest rate, r = 4.11% = 0.0411

n = number of times compounded per period, monthly = 12 (number of months in a year)

Total amount, F owed, after t years in college ;

F(t) = P(1 + r/n)^nt

F(t) = 15000(1 + 0.0411/12)^12t

F(t) = 15000(1.003425)^12t

2.) The annual percentage rate is the interest rate without compounding = 4.11%

3.)

The APY

APY = (1 + APR/n)^n - 1

APY = (1 + 0.0411/12)^12 - 1

APY = (1.003425)^12 - 1

APY = 1.04188 - 1

APY = 0.04188

APY = 0.04188 * 100% = 4.188%

7 0

2 years ago

A researcher obtained M = 27 for a sample of n = 36 scores selected from a population with µ = 30 and σ = 18. This sample mean c

dusya [7]

Answer:

True

Step-by-step explanation:

Given that:

M = 27, sample of n = 36 scores, µ = 30 and σ = 18.

The z score is used in statistics to determine by how many standard deviations the raw score is above or below the mean. If the z score is positive, the raw score is greater than the mean and if the z score is negative the raw score is less than the mean. The z score is given as:

$z=\frac{x-\mu}{\sigma}$