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3 years ago

Three consecutive integers add up to -6. the integers are

Mathematics

1 answer:

alina1380 [7]3 years ago

6 0

Answer:

-3, -2, -1

Step-by-step explanation:

you need to form an equation. We know that the integers are consecutive (meaning that they only have a difference of 1) so we could make an equation. x+(x+1)+(x+2)=-6. we solve the equation to get x=-3. We now know all the other numbers as well. -3+1=-2, -2+1=-2. The numbers are :-3, -2, -1

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Very confused on 1-3. please help

Arte-miy333 [17]

1. the length of side DA is 2
2. the length of side AB is 4
3. ∆ADF is congruent to ∆BDE because all three pairs of sides are equal to one another.
side AD is congruent to side BD.
side DF is congruent to side DE.
side EB is congruent to side FA.

6 0

3 years ago

The solution set x ≤ 2 or x ≥ 4 is consistent with an equation of the form

pshichka [43]

Answer:

B. |ax + b| ≥ c, where c is greater than zero.

Step-by-step explanation:

Given two inequalities $x\le 2$ and $x\ge 4.$

First, make the number in right parts of both inequalities the same by absolute value. You can reach this by subtracting 3:

$x\le 2\\ \\x-3\le 2-3\\ \\x-3\le -1$

and

$x\ge 4\\ \\x-3\ge 4-3\\ \\x-3\ge 1$

The two inequalities $x-3\le -1$ and $x-3\ge 1$ are equivalent to the ineguality

$|x-3|\ge 1$

Thus, option B is correct option.

4 0

3 years ago

Read 2 more answers

CEE

Aneli [31]

Looks like you have to attach a picture. It wont work, because all you did was copy it.

3 0

3 years ago

2.10 Guessing on an exam: In a multiple choice exam, there are 6 questions and 4 choices for each question (a, b, c, d). Nancy h

ololo11 [35]

Answer:

a) $p = (3/4)^5 *(1/4) =0.0593$

b) $P(X=6) = (6C6) (0.25)^6 (1-0.25)^{6-6}= 0.000244$

c) $P(X \geq 1)$

And we can use the complement rule like this:

$P(X \geq 1) = 1-P(X$

$P(X=0) = (6C0) (0.25)^0 (1-0.25)^{6-0}= 0.17798$

And replacing we have:

$P(X \geq 1) = 1-P(X$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: $P(A)+P(A') =1$

We can model the number of correct questions answered with a binomial distribution $X \sim Binom(n = 6, p = 1/4=0.25)$

Solution to the problem

Assuming the following questions:

a) the first question she gets right is the 6th question?

For this case we want the first 5 questions incorrect and the last one correct, assuming independence we have:

$p = (3/4)^5 *(1/4) =0.0593$

(b) she gets all of the questions right?

For this case we want all the questions right so then we want this:

$P(X=6) = (6C6) (0.25)^6 (1-0.25)^{6-6}= 0.000244$

(c) she gets at least one question right?

For this case we want this probability:

$P(X \geq 1)$

And we can use the complement rule like this:

$P(X \geq 1) = 1-P(X$

$P(X=0) = (6C0) (0.25)^0 (1-0.25)^{6-0}= 0.17798$

And replacing we have:

$P(X \geq 1) = 1-P(X$

7 0

3 years ago

Althea paid $5.00 each for two bracelets and later sold each for $15.00. She paid $8.00 each for three bracelets

____ [38]

Answer:

I have the same question

Step-by-step explanation:

message me if anyone helps I need it too

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3 years ago