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Vlad [161]
4 years ago
5

My brain capacity can not handle this one right now? Anyone good with geometry word problems? It’s number 12 if anyone is able t

o help out you are a blessing

Mathematics
1 answer:
densk [106]4 years ago
8 0

Check the picture below.

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What fraction of an hour is 8 minutes in simplest form
nikklg [1K]
1/15. 8/60 simplified down is 1/15
5 0
3 years ago
The area of a circle is 47.39cm2. find the length of the radius rounded to 2 dp.
Tpy6a [65]

The length of the radius rounded to 2 decimal points is 3.88cm.

In geometry, the area enclosed by a circle of radius r is pie  πr^2.

How to round decimals?

Rounding decimals consists of rounding a decimal number to a certain number of decimal places, to save time and help us express really long numbers in shorter terms. There are certain rules to follow when rounding a decimal number. Put simply, if the last digit is less than 5, round the previous digit down. However, if it’s 5 or more than you should round the previous digit up. So, if the number you are about to round is followed by 5, 6, 7, 8, 9 round the number up. And if it is followed by 0, 1, 2, 3, 4 round the number down.

The area of circle is 47.39cm^2.

Putting it in the formula we get

47.39cm^2 = πr^2

r^2 = 47.39 / π

r^2 = 15.0847

r = 3.88 cm

Hence the length of the radius rounded to 2 decimal points is 3.88cm.

Learn more about circles here :

brainly.com/question/22275589

#SPJ4

5 0
2 years ago
Can somebody explain to me what I need to do for this?
andrezito [222]

Answer:

Im pretty sure that you just have to find the value of X and Y...

4 0
3 years ago
An architect is designing a building each floor will be 12 ft tall write the equation for the number of floors the building can
12345 [234]
H = 12f
h = height of the building in feet
f = number of floors
3 0
3 years ago
Let f(x)=3x+2. What is f(2)?
puteri [66]

Answer:

\huge\boxed{\sf f(2) = 8}

Step-by-step explanation:

\sf Given \ that \ f(x) = 3x + 2 \\\\Put \ x = 2 \\\\f(2) = 3(2) + 2\\\\f(2) = 6+2\\\\\bold{f(2) = 8}\\\\\rule[225]{224}{2}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
3 0
3 years ago
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