The "origin" of a line is simply the points (0, 0)
To draw a line that passes through the origin (0, 0) & has a slope of 3/5, we simply start by drawing a point at (0, 0).
Then, from there, you use the slope to find your next points.
Slope = rise/run
So, 3 is the rise, and 5 is the run.
So, starting from (0, 0), you go up 3 times, and go to the right 5 times. So, (3, 5) is your next point. Just continue doing that and you'll get a line.
~Hope I helped!~
Answer:
The answer is....
Step-by-step explanation:
How many hours do you spend each week training for a sports league?
Taking
and differentiating both sides with respect to
yields
![\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B3x%5E2%2By%5E2%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B7%5Cbigg%5D%5Cimplies%206x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D0)
Solving for the first derivative, we have
Differentiating again gives
![\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B6x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B0%5Cbigg%5D%5Cimplies%206%2B2%5Cleft%28%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cright%29%5E2%2B2y%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D%3D0)
Solving for the second derivative, we have
Now, when
and
, we have
0.6=6/10 so after simplifying you get 3/5, hope it helps !!
Answer:
(f•g)(4) = 45
Step-by-step explanation:
f(x)=4x+1
g(x)=x^2-5
(f•g)(x) = 4(x^2 -5)+1
(f•g)(4) = 4(4^2 -5)+1
(f•g)(4) = 4(16-5)+1
(f•g)(4) = 4(11)+1
(f•g)(4) = 44 + 1
(f•g)(4) = 45
