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2 years ago

HELP ITS MY LAST QUESTION WITH STEP BY STEP

Mathematics

1 answer:

maks197457 [2]2 years ago

8 0

Answer:

Step-by-step explanation:

This is the answer because:

1) First, add Andy's score and Janet's score in order to know how much they got in total:

Janet's score: 119 + 96 + 145 = 360
Andy's score: 127 + 74 + 88 = 289

2) In order to find how much more Janet scored, jus subtract Andy's score from Janet's score:

360 - 289 = 71

Therefore, the answer is 71.

Hope this helps! :)

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Solve each rational equation

quester [9]

The answer would be x= 4,-4

8 0

3 years ago

Write two expressions for the perimeter of a square. Explain what information is in

Gnoma [55]

Two expressions for the perimeter of a square are:
4a
- a represents one side of the square
a + a + a + a
- a representa one side of the square

the first expression does not include any addition. But the two expressions are actually equivalent.

3 0

2 years ago

Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

3 years ago

Zacarías and paz together have $756.80 if Zacarías has $489.50, how much does Paz have? Write and solve an addition equation to

boyakko [2]

ANSWER: Paz have $267.30

STEP BY STEP EXPLANATION

Let be Z for Zacarías and P for Pax

Z+P= 756.80

Z= 489.50

P=756.8 - Z

P=756.80 - 489.50

P= 267.30

8 0

3 years ago

The sum of two

sergeinik [125]

Answer:

Step-by-step explanation:

let the two numbers be x,y (x>y)

Then x+y = 16 and x-y = 2

We know that (x+y)^2 - (x-y)^2 = 4xy

So 4xy = 16^2 - 2^2 => 4xy = (16+2)(16–2)

So xy = 18×14/4 = 63

Product of the numbers = 63

8 0

3 years ago