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Anuta_ua [19.1K]
3 years ago
14

How did technology change society in the Renaissance?

Engineering
2 answers:
WINSTONCH [101]3 years ago
8 0
I think it’s A


Hope I helped
solniwko [45]3 years ago
3 0

Answer:

Technology was able to meet many more social needs.

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Solid Isomorphous alloys strength
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Lol please give me points
5 0
3 years ago
16. Which polymers are recyclable?
MrRissso [65]

Answer:

Number 2 is HDPE, or High-Density Polyethylene. It is most commonly found in plastic bags, oil and detergent bottles, and toys. It is one of the simplest polymers to recycle. It is broken down into flakes, decontaminated and then reused for pipes, flower pots or reused as (non-food) bottles.

8 0
3 years ago
Diffusion of Ammonia in an Aqueous Solution Ammonia (A)-water (B) solution ta 278 K and 4 mm thick is in contact with an organic
Tom [10]

Answer:

Explanation:

The pictures below shows the whole explanation for the problem

4 0
4 years ago
Air flows through a device such that the stagnation pressure is 0.4 MPa, the stagnation temperature is 400°C, and the velocity i
RoseWind [281]

To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.

The stagnation temperature can be defined as

T_0 = T+\frac{V^2}{2c_p}

Where

T = Static temperature

V = Velocity of Fluid

c_p = Specific Heat

Re-arrange to find the static temperature we have that

T = T_0 - \frac{V^2}{2c_p}

T = 673.15-(\frac{528}{2*1.005})(\frac{1}{1000})

T = 672.88K

Now the pressure of helium by using the Adiabatic pressure temperature is

P = P_0 (\frac{T}{T_0})^{k/(k-1)}

Where,

P_0= Stagnation pressure of the fluid

k = Specific heat ratio

Replacing we have that

P = 0.4 (\frac{672.88}{673.15})^{1.4/(1.4-1)}

P = 0.399Mpa

Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa

<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>

3 0
3 years ago
The reading on a mercury manometer at 70(°F) (open to the atmosphere at one end) is 25. 62(in). The local acceleration of gravit
Ilya [14]

The absolute pressure in psia being measured is; 27.228 psia

<h3>What is the absolute Pressure?</h3>

Formula for absolute Pressure is;

Absolute pressure = Atmospheric pressure + Gauge pressure

P_{abs} = P_{atm} + P_g

We are given;

P_atm = 29.86 (in Hg) = 14.666 psia

Density of mercury at 70 °F; ρ = 13.543 g/cm³

Mercury Manometer reading; h = 25.62 in

Acceleration due to gravity; g = 32.243 ft/s²

Gauge pressure of the mercury = ρgh = 13.543 * 25.62 * 32.243

When we multiply and covert to psia gives; P_g = 12.562 psia

Thus;

P_abs = 14.666 + 12.562

P_abs = 27.228 psia

Read more about Absolute Pressure at; brainly.com/question/17200230

7 0
2 years ago
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