Answer:
4.13 MPa
Explanation:
Given
Modulus of elasticity = E = 102 GPa
E = 102 * 10^9
Modulus resilience U = 0.79 * 106Pa
Modulus of Resilience U = y²/2E --- Make y the subject of formula
y² = 2EU
y = √(2EU)
y = √(2 * 102 * 10^9 * 0.79 * 106)
y = √1.708296E13
y = 4133153.759540044
y = 4.13E6
y = 4.13MPa
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Answer:
See explanations for completed answers
Explanation:
Given that; The average grain diameter of an aluminum alloy is 14 mu m with a strength of 185 MPa. The same alloy with an average grain diameter of 50 mu m has a strength of 140 MPa. (a) Determine the constants for the Hall-Patch equation for this alloy, (b) How much more should you reduce the grain size if you desired a strength of 220 MPa
See attachment for completed solvings