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aliina [53]
3 years ago
12

You need to determine the mass of an aqueous solution. You determine the mass of your 10.0 mL graduated cylinder to be 23.099 g.

After adding a volume of 3.09 mL of solution to the cylinder, you reweigh it and determine the new mass to be 26.050g.
What is the mass of the aqueous solution in grams?
Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

The mass of the aqueous solution in grams is obtained by subtracting mass of the 10.0 mL graduated cylinder alone from  the mass of the cylinder + solution. Therefore mass of the solution is 2.951 g.

We have from the question, the following information;

Mass of empty 10.0 mL graduated cylinder to be 23.099 g

Mass of 10.0 mL graduated cylinder +  3.09 mL of solution to be 26.050g

Mass of aqueous solution in grams = mass of the cylinder + solution - mass of the 10.0 mL graduated  cylinder alone

= 26.050g - 23.099 g

= 2.951 g

Learn more: brainly.com/question/5048248

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Answer:

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Explanation:

Let us first identify the dissociation equation for this weak acid,

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