Solution :
It is given that :
Weight of the antacid tablet = 5.4630 g
4.3620 gram of antacid is crushed and is added to the stomach acid of 200 mL and is reacted.
25 mL of the stomach acid that is partially neutralized required 13.6 mL of NaOH to be titrated for a red end point.
27.7 mL of 
solution is equivalent to 
of the original stomach acid. Therefore, 13.6 mL of NaOH will take x 
= 12.27 ml of the original stomach acid.
Answer:
19.32 g/cm³
Explanation:
The density will remain the same no matter how many times you cut the gold. The density is g/cm³ or g/mL. Density is essentially how many grams 1 mL of a compound weighs.
The answer is b, corporation
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