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shtirl [24]
3 years ago
7

Which is the common ion when sodium sulfate is added to a solution of barium sulfate? na + ba 2+ so4 2 –?

Chemistry
2 answers:
OleMash [197]3 years ago
8 0

The correct answer is S042-

aliya0001 [1]3 years ago
6 0

The compound sodium sulfate is made of sodium ion and sulfate ion.

The formula can be written as Na₂SO₄.

The cation present in this compound is Na⁺ and the anion is SO₄²⁻.

The compound barium sulfate is made of barium ion and sulfate ion.

The formula can be written as BaSO₄.

This compound contains the cation Ba²⁺ and anion SO₄²⁻.

From the above , we can see that both the compounds have common anion which SO₄²⁻

So, the sulfate, SO₄²⁻ is the common ion when sodium sulfate is added to a solution of barium sulfate

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vlabodo [156]

Answer:

hydrogen atom and oxygen atom

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3 years ago
25. Which of the following is represented in the highest percentage by volume in dry air? A. Carbon dioxide B. Hydrogen C. Nitro
emmasim [6.3K]
The correct option is C. Nitrogen gas has the highest percentage by volume of all the gases that make up the air.
The composition of the air is as follows:
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8 0
4 years ago
Which element do you expect to be most like magnesium? Why?
Volgvan
I know its calcium, just not 100% sure why.
5 0
3 years ago
How do subscripts represent the charge balance of ions
finlep [7]
<h3><u>Answer and explanation</u>;</h3>
  • To balance the charges of ions the number of electrons lost is equal to the number of electrons gained. The overall net charge must be zero.
  • The number of ions needed to accomplish this is represented by the subscripts.
  • For any given ionic compound, the product of the charge on the ion (or multiatomic ionic group) times the subscript of the ion will give a total charge of zero when all ions are considered.

For examples: NaCl Na = +1 Cl = -1 total is zero

5 0
4 years ago
A sample weighing 3.110 g is a mixture of Fe 2 O 3 (molar mass = 159.69 g/mol) and Al 2 O 3 (molar mass = 101.96 g/mol). When he
grandymaker [24]

Answer:

The mass fraction of ferric oxide in the original sample :\frac{723}{3110}

Explanation:

Mass of the mixture = 3.110 g

Mass of Fe_2O_3=x

Mass of Al_2O_3=y

After heating the mixture it allowed to react with hydrogen gas in which all the ferric oxide reacted to form metallic iron and water vapors where as aluminum oxide did not react.

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

Mass of mixture left after all the ferric oxide has reacted = 2.387 g

Mass of mixture left after all the ferric oxide has reacted = y

x=3.110 g- y=3.110 g - 2.387 g = 0.723 g

The mass fraction of ferric oxide in the original sample :

\frac{0.723 g}{3.110 g}=\frac{723}{3110}

5 0
4 years ago
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