What is the domain and range of the graph?

two sides of a triangle measures 25 cm + 35 CM which of the following would be the measure of the third side

Oxana [17]

Assuming those are the legs of the triangle and that you need to find the hypotenuse... I would use the formula: a^2+b^2=c^2
It doesn't matter what a and b are, just fill it in.
25^2+35^2=c^2
625+1225=c^2
1850=c^2
Take the square root of 1850, it isn't a perfect square so I got: 43.01.
If you want, just round it to 43, idc.
So, if I were to check my work, I would need to remember that the hypotenuse is the longest side.
Since 43 is the hypotenuse, it is the longest side.

5 0

3 years ago

Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol

aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let A = boards have solder defects and B = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

$P(A\cap B)=P(A)\times P(B)$

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

$=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09$

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

$P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018$

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

$P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118$

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0

3 years ago

Can someone please help me with this proof?!

Elza [17]

Answer:

because AC and BD bis => AX = XC; BX = XD

ΔAXD ≅ ΔCXB (SAS) because: AX = CX

DX = BX

m∠AXD = m∠BXC ( 2 opposing angles)

because ΔAXD ≅ ΔCXB (SAS)

=> AD = BC and m∠DAX = m∠BCX

because m∠DAX = m∠BCX => AD//BC

ABCD has AD = BC and AD//BC => ABCD is a parallelogram

Step-by-step explanation:

4 0

3 years ago

2[( 62 -52) + 4] Need help

luda_lava [24]

Answer:

28

Step-by-step explanation: USE PEDMAS

2[(62-52)+4] = 2[(10)+4]= 2[14]=28

5 0

2 years ago

Dkendbdjdbebdbdbdjdnd

sertanlavr [38]

Answer:

5/2

Step-by-step explanation:

The 5^-3 and 5^6 cancel out to be 5^3. Then the 5^3 cancels out with the 5^2 in the denominator and leaves you with just a 5. The 2^2 makes the 2^3 in the denominator just 2. So, you are left with 5/2! Hope this helps.

7 0

2 years ago