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1 year ago

6

What is the solution to -55+q=7 A. a=-62 B. q=62 C. q=42 D. q=-42

2 answers:

Scorpion4ik [409]1 year ago

4 0

Answer:

C, as q = 62.

Step-by-step explanation:

When you have an equation, your goal is to get the letter you are solving for alone. To do this, you employ a simple rule: what you do to one side of the equals sign, you must do the other.

To isolate q in -55 + q = 7, you must add 55 to the left side. q is now alone. However, because we added 55 to the left side, we must also do it to the right! 7 + 55 = 62, so the new right side is 62. Hence, we get to this:

q = 62

The answer is now in plain sight!

Elan Coil [88]1 year ago

3 0

C (62) -55-7= 62

Hope this helps

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The ordered pairs of the solution to the system of equation are [(3, 6), (-3, 18)]

<h3>System of equations</h3>

Given the following system of equations expressed as:

f(x) = x² - 2x + 3 and f(x) = -2x + 12

Since they are both function of x, hence;

x² - 2x + 3 = -2x + 12

x² - 2x + 3 + 2x - 12 = 0

x² - 9 = 0

x² = 9

x = ±√9

x = ±3

If x = 3

f(x) = -2(3) + 12

f(x) = 6

If x = -3

f(x) = -2(-3) + 12

f(x) =18

Hence the ordered pairs of the solution to the system of equation are [(3, 6), (-3, 18)]

Learn more on system of equation here: brainly.com/question/14323743

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6 0

1 year ago

Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples

zheka24 [161]

Answer: a. 0.40 b. 0.23 c . 0.435 d . 0.25

Step-by-step explanation:

melanin content Total

high low

moisture high 13 10 23

content low 47 30 77

Total 60 40 <u> </u><u>100</u>

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)= $\dfrac{40}{100}=0.40$

b) Total skin samples has high moisture content = 13+10=23

P(B) = $\dfrac{23}{100}=0.23$

c) A ∩ B = Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) = $\dfrac{10}{100}=0.10$

Using conditional probability formula , $P (A|B)=\dfrac{P(A\cap B)}{P(B)}$

$P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435$

d) $P (B|A)=\dfrac{P(A\cap B)}{P(A)}$

$P (B|A)=\dfrac{0.10}{0.40}=0.25$

8 0

2 years ago