Standard for is x × 10 ^I
where,
I = indice
10 > x < 0
you cannot write this is standard form with putting in what they stand for. However you can simplify it -
4(8m-7n) +6(3n-4m)
32m - 28n + 18n - 24m
8m - 10n
but hey I am from England do what we call standard form might be different
y=3x, y=(2/7)x,-0.5=y are all on direct the other ones are on the other side i just did the question they correct. :)
<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
Answer: Horizontal asymptote is 
and vertical asymptotes are 
Step-by-step explanation:
Since we have given that
We need to find the horizontal and vertical asymptotes.
Since vertical asymptotes will occur where the denominator becomes zero.
So, here denominator is 
Now,
And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.
Hence, horizontal asymptote is and vertical asymptotes are
Answer:
A zero-order table is simply a table showing variables
controlled for. As an example, given an equation of two variables,
this table shows the values that result from the available values
for those two variables.
