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podryga [215]
3 years ago
5

If there was a circle and i wanted to find out the area.

Mathematics
1 answer:
iragen [17]3 years ago
6 0
The formula for the area of a circle is πr^2
r means radius.
If the radius is 5, then r = 5.
This means the equation for the area is π(5)^2
π is about equal to 3.14.
So we can replace π with 3.14.
(3.14)(5)^2
According to the order of operations, the first step to solve this is to do 5^2, which is exponents.
5^2 = 25
Next, multiply.
25 • 3.14 = 78.5
So the area of the circle with a radius of 5 is approximately 78.5 square units.
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1) Complete the following items dealing with sets.
Ivanshal [37]
From the set {21, 37, 45}, use substitution to determine which value of x makes the inequality true.x - 8 > 29 
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none of these 
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21From the set {21, 37, 45}, use substitution to determine which value of x makes the inequality true.x - 8 > 29 
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3 0
3 years ago
If "z" is a standard normal variable, find the probability that "z" is less than 1.16. Sketch the graph and the required area.
mixer [17]

Answer:

Step-by-step explanation:

It would be more obvious if it says z is a standard Normal variable and that the question is related to statistics.

From "Computing Probabilities Using the Cumulative Table" , the probability of z is less than 1.16, P(z<1.16) = 0.8770.

7 0
2 years ago
The value of x varies directly with y, and when x=1/3,y=5
pickupchik [31]

Answer: y = 36x

Step-by-step explanation: Given that x and y vary directly then the equation relating the is

y = kx ← k is the constant of variation

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3 0
2 years ago
(a - b)(a 2 + ab + b 2) HELP
Mila [183]
Hey there :)

( a - b )( a² + ab + b² )
Let us distribute ( a - b ) into the other

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a³ + a²b + ab² - a²b - ab² - b³

We can further simplify
a²b - ab² = 0
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You can see in the picture which I have attached. It is the 8th formula

7 0
3 years ago
Read 2 more answers
Gcf of 9 46 7 21 18 12 15 25 55
Taya2010 [7]

1 because the only factors of 7 are 1, 7. Numbers like 9 and 46 and 18 and 12 and 15 and 25 and 55 do not have a factor of 7.

4 0
3 years ago
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