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soldier1979 [14.2K]
3 years ago
8

Penni is making a mosaico pattern with 2-inch square tiles. The area she wants to cover is 8 inches by 4 inches. How many tiles

does she need?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0

Answer:

8 Tiles

Step-by-step explanation:

Dimension of area to be covered =8 inches by 4 inches

  • Area to be covered = 8 X 4 =32 Square Inches

Penni intends to use 2-inch square tiles.

  • Area of One Tile =2 X 2=4 Square Inches

Therefore, the number of tiles to be used by Penni

=Area to be covered Divided by Area of One Tile

= 32/4

=8

Therefore, Penni needs 8 Tiles.

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Find m/ GJI<br> a. 15<br> b. 75<br> c.100<br> d. 105
sertanlavr [38]
M<GJI=(x+60)°=?

We need to find x. The angle GJI and FJH are opposite by the the vertex, then they must be congruents:
(x+60)°=(5x)°
x+60=5x
Solving for x
x+60-x=5x-x
60=4x
60/4=4x/4
15=x
x=15

Replacing x by 15 in m<GJI:
m<GJI=(x+60)°=(15+60)°→m<GJI=75°

Answer: Option b. 75
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Yolanda has a piece of rectangular fabric measuring 30 centimeters by 9 centimeters. She uses half of the material to make a pup
IRINA_888 [86]
It is 67.5 centimeters
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A metal company's old machine makes bolts at a constant rate of 100 bolts per hour.The company's new machine makes bolts at a co
zloy xaker [14]

Answer:72minutes B

Step-by-step explanation:

100t + 150t =300

250t =300

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7 0
3 years ago
Read 2 more answers
Is it possible for a 5 digit number to be rounded to a 6 digit number
IrinaK [193]
When we round a number the new rounded <span>number is </span>simpler but the value is kept close to what it was. The common method for rounding numbers is the following: we d<span><span>ecide which is the last digit to keep and l</span><span>eave this digit the same the same if the next digit is less than 5 or increase it by 1 if the next digit is bigger than 5.
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Solve the equation 2^(2x+1)+8=17×2^x.
myrzilka [38]
Oooh, looks fun

ok
erm
we might want to know some properties
(x^m)(x^n)=x^{m+n}
(a^b)^c=a^{bc}
if a^m=a^n where a=a, then assume m=n

2^{2x+1}=(2^{2x})(2^1)
so
(2^{2x})(2)+8=17(2^x)
(2^{2x})(2)+2^3=17(2^x)
(2^x)^2(2)+2^3=17(2^x)
minus 17*2^x both sides
(2^x)^2(2)+2^3-17(2^x)=0
use u subsitution, u=2ˣ
(u)^2(2)+2^3-17(u)=0
solve 2u^2+8-17u=0
or
2u^2-17u+8=0
ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8

2u-1=0
2u=1
u=1/2

now
u=2ˣ

8=2ˣ
2^3=2^x
3=x

and
\frac{1}{2}=2^x
2^{-1}=2^x
-1=x

x=-1 and 3
neat problem
8 0
3 years ago
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