What’s the area of the above figure which has sides of length 6 And 8

The diagonals of a Rhombus are 2Dm and 3M. What’s is the area of the Rhombus??

NemiM [27]

Answer:

336 $m^{2}$

Step-by-step explanation:

Area of Rhombus = (1/2)*xy

Where x and y are length of diagonals

Area = (1/2) * 21 * 32 = 21* 16 = 336

Area = 336 m²

7 0

3 years ago

The area of a rectangle is 42 ft squared, and the length of the rectangle is 5 ft more than twice the width. Find the dimensions

stira [4]

Answer:

<h3>Length = 12 ft</h3>

Width = $\frac{7}{2} ft$

Step-by-step explanation:

Given,

Area of rectangle = $42 \: {ft}^{2}$

Width = X

Length = 2x + 5

Now,

$x(2x + 5) = 42$

$2 {x}^{2} + 5x = 42$

$2 {x}^{2} + 5x - 42 = 0$

$2 {x}^{2} + 12x - 7x - 42 = 0$

$2x(x + 6) - 7(x + 6) = 0$

$(2x - 7)(x + 6) = 0$

Either

$2x - 7 = 0$

$2x = 0 + 7$

$2x = 7$

$x = \frac{7}{2}$

Or,

$x + 6 = 0$

$x = 0 - 6$

$x = - 6$

Negative value can't be taken.

So, width = $\frac{7}{2} ft$

Again,

Finding the value of length,

Length = $2x + 5$

$2 \times \frac{7}{2} + 5$

$7 + 5$

$12$

Length = 12 ft

7 0

3 years ago

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What is 9/10 of a yard

igor_vitrenko [27]

(9/10)x3 feet
= (9/10)x36 inches
= 32.4 inches

4 0

3 years ago

Find the greatest and least number from 5,0,8,9 and 7

Dvinal [7]

<u>Answer:</u>

Greatest number: 98750
Least number: 5789

<u>Explanation:</u>

<em>To find the greatest number with the following values, we must arrange the numbers in descending form. </em>

<em>=> We can clearly tell that the numbers in descending form is 9 > 8 > 7 > 5 > 0</em>

<u>Hence, the greatest number with the following numbers (5,0,8,9, and 7) will be 98750.</u>

<em>To find the least number with the following values, we must arrange the numbers in ascending form.</em>

<em>=> We can clearly tell that the numbers in ascending form is 0 < 5 < 7 < 8 < 9</em>

<u>Hence, the least number with the following numbers (5,0,8,9, and 7) will be 5789</u>

6 0

2 years ago

Find the midpoint of PQ<br><br> P(4 1/3, 3 1/6), Q(-2 1/5, 3 2/3)

Paha777 [63]

Answer:

$(1\frac{1}{15},3\frac{5}{12})$

Step-by-step explanation:

To find the midpoint, you must average the x's then average the y's.

So the x's are $4 \frac{1}{3}$ and $-2\frac{1}{5}$ .

The y's are $3\frac{1}{6}$ and $3\frac{2}{3}$ .

To find an average of a data with 2 elements you must add the two elements then take that sum and divide it by 2.

So this is what we will do with the x's then the y's.

So first x:

$\frac{4\frac{1}{3}+-2\frac{1}{5}}{2}$

Write as improper fractions:

$\frac{\frac{13}{3}+\frac{-11}{5}}{2}$

Division by 2 is the same as multiplying by 1/2:

$\frac{13}{6}+\frac{-11}{10}$

The least common multiple of 6 and 10 is 30. We will multiply first fraction by 5/5 and 3/3 for the second so we can have the same denominator.

$\frac{65}{30}+\frac{-33}{30}$

Now that the bottoms are the same we can write as one fraction:

$\frac{65+-33}{30}$

Simplify:

$\frac{32}{30}$

If you want the answer as a mix fraction like your question began as we can do that by first figuring out how many 30's are in 32 and what is the remainder of that division.

There is one 30 and 32 and so 32-30=2 is the remainder.

$1\frac{2}{30}$

Reduce by dividing top and bottom by 2:

$1\frac{1}{15}$

Now for y:

$\frac{3\frac{1}{6}+3\frac{2}{3}}{2}$

Write the mix fractions as improper fractions:

$\frac{\frac{19}{6}+\frac{11}{3}}{2}$

Dividing by 2 is the same as multiplying by 1/2:

$\frac{19}{12}+\frac{11}{6}$

The least common multiple of 12 and 6 is 12 so I'm going to multiply the second fraction by 2/2 so the denominators will be the same:

$\frac{19}{12}+\frac{22}{12}$

Since the denominators are the same we can write as a single fraction:

$\frac{41}{12}$

How many 12's are in 41? 3 and so the remainder is 41-3(12)=41-36=5.

$3\frac{5}{12}$

So the midpoint is:

$(1\frac{1}{15},3\frac{5}{12})$ .

6 0

3 years ago

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