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vekshin1
3 years ago
15

Subtract. - 3 3/8 - 7 8 Enter your answer, in simplest form, in the box.

Mathematics
1 answer:
Georgia [21]3 years ago
8 0

Answer:

the answer is there

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Sales tax is 6%. Bought car for$820 what was cost of car
pogonyaev
820 + .06(820)
820 + 49.2
869.2
The cost of the car is $869.20.
8 0
4 years ago
Read 2 more answers
What is the mean of the following set of data? Round your answer to two decimal places. 130, 110, 121, 141, 137, 136, 103, 144
bearhunter [10]
127.75
130+110+121+141+137+136 /6
=10228/6
=127.75

8 0
3 years ago
The manager of the video department at a department store plans to purchase a large number of DVDs of a recent movie. One suppli
Vera_Pavlovna [14]

Answer:

1 box of 20 and 1 box of 14

They will cost $410

Step-by-step explanation:

1. Find how many boxes of 20 DVD movies can be bought

415 - 240 = 175

1 box of 20 DVD movies can be sold

2. Find how many boxes of 14 DVD movies can be bought from $175

175 - 170 = 5

1 box of 14 DVD movies can be bought

3. Find the cost

240 + 170 = 410

8 0
3 years ago
Two water pumps are filling a pool. One of the pumps is high power and can fill the pool 5 hours before the other can do. Howeve
9966 [12]

L = hours for the slower pump to fill the pool

L - 5 = hours for the high power pump, since it can do it in 5 hours less.

since the slower pump takes L hours, the faster pump takes then L - 5 hours.

we know both pumps together take 3 hours to do <u>half of the pool</u>, so that means that to fill up <u>the whole pool it takes them 6 hours</u>.

since the slower pump can do it alone in L hours, in 1 hour it has done 1/L of the whole thing.

likewise, since the faster pump can do it in L-5 hours, in 1 hour alone it has done 1/(L-5) of the whole job.


\bf \stackrel{\textit{slower pump's rate}}{\cfrac{1}{L}}~~~~+\stackrel{\textit{faster pump's rate}}{\cfrac{1}{L-5}}~~~~=~~~~\stackrel{\textit{total done in 1 hour}}{\cfrac{1}{6}} \\\\\\ \textit{let's multiply both sides by }\stackrel{LCD}{6(L)(L-5)}\textit{ to do away with the denominators} \\\\\\ 6(L)(L-5)\left( \cfrac{1}{L}+\cfrac{1}{L-5} \right)=6(L)(L-5)\left( \cfrac{1}{6} \right)


\bf 6(L-5)+6L=(L)(L-5)\implies 6L-30+6L \\\\\\ 12L-30=L^2-5L\implies 0=L^2-17L+30 \\\\\\ 0=(L-15)(L-2)\implies L= \begin{cases} \boxed{15}\\ 2 \end{cases}


now, we can't use L = 2, because, the whole job by both is done in 6 hours, there's no way the slower pump can do it in less than that, so L = 15.

now if L = 15, then L - 5 = 10.

5 0
4 years ago
Consider the functions p and q.
xz_007 [3.2K]

Answer:

q= -1x

coordinates of p are .5, 2

Step-by-step explanation:

I apologize if I'm wrong love

6 0
2 years ago
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