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3 years ago

12

Doug had about $3,215 in savings while his brother had double that amount in savings. What is a reasonable amount that the broth

ers have saved?

2 answers:

love history [14]3 years ago

8 0

You would have to first multiply 3215x2 then you get the answer and then you add 3215 +3215x2

MaRussiya [10]3 years ago

5 0

Answer: i think you would have to multiply

Step-by-step explanation:

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Item 19 A plant has an initial height of 1 inch and grows at a constant rate of 3 inches each month. A second plant that also gr

Alex777 [14]

3 months, i just answered this same question lol.

3 0

3 years ago

Fred has 45 books. Sally has 27 times more books than Fred. How many books does Sally have?

hodyreva [135]

Answer:

fred = 45 books

sally has 27 times more book than fred

sally = 45 X 27

= 1215 books

5 0

3 years ago

The Supreme Court of the United States is mainly an appellate court, meaning A) it cannot hear a case the first time. B) it is t

dimaraw [331]

Your answer should be D hope this helps

8 0

3 years ago

Read 2 more answers

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

1. What are two numbers that multiply to make -24 and sum to make -5?

charle [14.2K]

1) -8 and 3
because -8+3= -5 and -8x3=24
2) -8 and -5
because -8-5=-13 and -8x-5=40

8 0

3 years ago