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inn [45]
3 years ago
10

A function is created to represent amount of money spent on lunch if you spent five dollars a day. What restrictions would be ma

de to the range?
A. The range would only include integers
B. The range would only include negative integers
C. the range would only include positive integers
D. the range would include allreal number
Mathematics
1 answer:
sergejj [24]3 years ago
4 0
D. the range would include all real numbers.
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Please help me..thx!
GarryVolchara [31]

Answer:

x=25

Step-by-step explanation:

X=180-125-30

x=25

5 0
3 years ago
The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is
Akimi4 [234]

Answer:

(5, -6)

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Find the least number which is exactly divisible by 15 , 20, 25 <br>explain step by step​
padilas [110]

Answer:

<h3>ans is 300</h3>

Step-by-step explanation:

<h3>you need to take LCM of 15,20,25 </h3><h3>and their LCM Will be 300</h3>

<h3>I'M NOT PRETTY SURE ABOUT IT. ...</h3>
3 0
3 years ago
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Find an equation for the line that passes through the points (-1,2) and (5,5)
sesenic [268]

Answer:

-The equation for the problem:

y = \frac{1}{2}x + \frac{5}{2}

Step-by-step explanation:

-First, you need determine the slope of a line:

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} (where (x_{1},y_{1}) is the first coordinate and (x_{2},y_{2}) is the second coordinate).

-Use both points (-1,2) and (5,5) for the formula:

m = \frac{5-2}{5+1}

m = \frac{3}{6}

m = \frac{1}{2}

-After you have found the slope, use the point-slope formula and use the slope \frac{1}{2} and the first coordinate, which is (-1,2), to solve the equation and put it in slope-intercept form:

y-y_{1} = m (x-x_{1})

y-2 = \frac{1}{2}  (x+1)

-Solve:

y-2 = \frac{1}{2}  (x+1)

y-2 = \frac{1}{2}x + \frac{1}{2}

y = \frac{1}{2}x + \frac{5}{2}

So, therefore the equation is y = \frac{1}{2}x + \frac{5}{2} .

8 0
4 years ago
Solve this system by graphing both<br> equations. Use the grid below.<br> {y = -2x + 6<br> {y= 4x
Free_Kalibri [48]

Answer:

For the given linear equation in two variables, the solution to the system of equations is (-2, -6).

Given :

y = x - 4 ---- (1)

y = 4x + 2----- (2)

Linear equations are nothing but yet another subset of "equations". Any linear calculations requiring more than one variable can be done with the help of linear equations.

The standard form of a linear equation in two variables is of the form. Here, x and y are variables, and a, b and c are constants.

From equations (1) and (2) we get,

x-4 = 4x + 2

x = - 2

Now, from equation (1) we get,

y = -2 -4

y = - 6

The solution to the system of equations is (-2, -6).

5 0
2 years ago
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