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shepuryov [24]
3 years ago
8

El area de un triangulo es de 432 unidades cuadradas. ¿Cual es la altura y la base sabiendo que la base mide tres veces su altur

a?
Mathematics
1 answer:
Lelu [443]3 years ago
8 0

Usando el concepto del área del triángulo, se encuentra que :

  • La altura es de 16.97 unidades.
  • La base es de 50.91 unidades.

---------------------------

El área del triángulo de base b y altura h es dada por:

A = \frac{bh}{2}

---------------------------

  • El area es de <u>432 unidades quadradas</u>, o sea, A = 432
  • La base mide <u>tres veces su altura</u>, o sea, b = 3h

---------------------------

<u>Reemplazando en la ecuación para el área</u>, es posible encontrar la altura:

A = \frac{bh}{2}

432 = \frac{3h \times h}{2}

3h^2 = 864

h^2 = \frac{864}{3}

h^2 = 288

h = \sqrt{288}

h = 16.97

La altura es de 16.97 unidades.

---------------------------

La base es dada <u>en funcion da altura,</u> o sea:

b = 3h = 3(16.97) = 50.91

La base es de 50.91 unidades.

Se da un problema similar en brainly.com/question/23931350

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