For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points through which the line passes, so we can find the slope:

Thus, the equation is of the form:

We substitute one of the points and find "b":

Finally, the equation is of the form:

ANswer:

Answer:
Step-by-step explanation:
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Slope Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Choose any 2 points from the chart.</em>
Point (-6, 11)
Point (-2, 1)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:

- Subtract/Add:

- Simplify:

Seven weeks until they meet again
Let's call animals "a", and birds "b", birds of prey, "p"
so, b=

and p=

what;s the relation of p to a?
we substitude b into the last one:
and p=

so:
p=

p=

p=

p=

which is the answer!