So c is located at -50 from 0, and d is 50 from 0. we could just say that c+d=?
0 is 50 away from c, so c=50, d is 50 away from 0 so d=50, now we just add 50+50=100, answer is 100
:)
F(x) = 3x -1
g(x) = x+2
so
(f+g)(x) = 3x -1 + x+2
(f+g)(x) = 4x + 1
answer is C. 4x + 1
What is that actual equation
<span>The parent cosine function can be transformed and translated. So, from the basic function cos(x) we can obtain function acos(bx+c). In our case, a=3- amplitude, b=10- the period change and c=-pi- the phase shift. So, the parent cosine function is mutiplied with 3 (which gives the amplitude of the function, 3*0.5=1.5). The period of the function is changed, and is 2pi/b=2pi/10=pi/5 and the cos(x) is phase shifted for c/b=-pi/10.</span>
