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3 years ago

I need help I'm struggling with questions 3 and 4

Mathematics

2 answers:

Charra [1.4K]3 years ago

3 0

Answer: Part C is $57.5

Part C: Mai is being charged $5.75 per(1) day and since it takes Mai to pay off her debt the equation would be 5.75 x 10 = 57.5

So $57.5 dollars

harina [27]3 years ago

3 0

9514 1404 393

Answer:

c. -$69.97

d. not enough

Step-by-step explanation:

c. The late fee is another withdrawal from Mai's account. After 10 days, the total amount withdrawn to pay late fees is 10(-5.75) = -57.50. At that point in time, Mai's account balance will be ...

-$12.47 -10(5.75) = -$69.97 . . . . Mai's balance after 10 days

d. Mai's balance after 5 days will be calculated the same way:

-$12.47 -5(5.75) = -$41.22

Even if she adds $40 to her account, the balance will be ...

-$41.22 +40.00 = -$1.22 . . . . a negative number; still subject to late fees

Adding $40 on day 5 is not enough to avoid further late fees.

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3 years ago

What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*

pickupchik [31]

<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation $x^4-41x^2=-400$ .

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

$x^4-41x^2+400=-400+400$ .

$x^4-41x^2+400=0$ .

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

$x^4-25x^2-16x^2+400=0$

Making it into two groups, we get

$(x^4-25x^2)+(-16x^2+400)=0$

Factoring out GCF of each group, we get

$x^2(x^2-25)-16(x^2-25)=0$

$(x^2-25)(x^2-16) =0$

Factoring out $(x^2-25)$ and $(x^2-16)$ separately by difference of the squares identity $a^2-b^2=(a-b)(a+b)$ , we get

$(x^2-25) = x^2-5^2= (x-5)(x+5)$ and

$x^2-16 = x^2-4^2 =(x-4)(x+4)$ .

Therefore,

$(x-5)(x+5)(x-4)(x+4) =0$

Applying zero product rule,

x-5=0

x+5=0

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x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

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