Answer:
171 newspapers.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

How many newspapers should the newsstand operator order to ensure that he runs short on no more than 20% of days
The number of newspapers must be on the 100-20 = 80th percentile. So this value if X when Z has a pvalue of 0.8. So X when Z = 0.84.




So 171 newspapers.
Answer:
Highest to lowest the numbers would be (1/2)^2, (-1)^2, -1 2/5 Putting the "bar 4" somewhere
First we need the numbers exact value meaning
-1 2/5 = -1.4
(-1)^2 = -1
?4 = ?
(1/2)^2 = 0.25
I think it is 1.6
sorry if i am wrong