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1 year ago

CAN SOMEONE PLZ HELP ME WIT THIS

Mathematics

1 answer:

frez [133]1 year ago

4 0

Put one point on U and put the other point on V. Then put the U point on the U point and make a line like ) with the same length as the last line. Then use a straight edge and a draw a line threw it

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Trisha runs 3 miles every 50 minutes. At this rate, how many minutes did Trisha run in 12 miles?

SVEN [57.7K]

Answer:

200 minutes ; 3 hours and 20 minutes.

Step-by-step explanation:

If you write a proportion in the form

miles/minutes = miles/minutes

you would get 3/50 = 12/x

from there you cross multiply to get

3x=600, and solve that to get 200 minutes.

another way was to see that 12 is 3*4, and multiply 50 by 4 to get the same answer.

5 0

2 years ago

A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th

ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\$

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

$H_0: \mu=500\\\\H_a:\mu< 500$

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1$

The degrees of freedom for this sample size are:

$df=n-1=5-1=4$

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0

2 years ago

What expression is equivalent to the expression 2(6y-4)

Kobotan [32]

Answer:

12y-8

Step-by-step explanation:

If you distribute the 2 you will 12y-8

4 0

2 years ago

What fracción is 20% of 40

lions [1.4K]

20 percent of 40 is 8. As a fraction that would be 8/1.

Hope this helps

6 0

2 years ago

a game is played with tokens according to the following rule and each round the player with the most tokens gives one token to e

gulaghasi [49]

Answer:

47 rounds and Eve wins.

Step-by-step explanation:

If read right, the highest player, (player with the most tokens) has to lose 3 tokens each round, so starting off with Evelyn, 17 - 3 = 14, and the other two each have +1 added to them, so, E=14, A=17 V=16, now subtract three from A (Amelia) and don't forget that one token is always being discarded each round. So the toal number of tokens at the start was 48, (17 + 16 + 15) so right now the total tokens should be 47, which it is. now starting the second round, A gives up 3 tokens so, 17 -3, again equals 14 and each of the two other players get one token, so E=15, A=14 V=17. Now you know the general trend, so we can figure this out seeing that after each round the number of tokens decrease by one, so there will be a round till all tokens are out except one, so there will be 47 rounds and since E started with the highest number they will win.

8 0

1 year ago