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2 years ago

Find the greatest common factor of 13x2 and 14x3

Mathematics

1 answer:

mamaluj [8]2 years ago

8 0

Answer:

Step-by-step explanation:

13x2=26

14x3=42

Greatest common Factor of 26 and 42 is 2

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Find the measure of the indicated angle to the nearest degree.

deff fn [24]

Given:

A right triangle with legs 5 units and 6 units.

To find:

The measure of angle opposite of side whose length is 5 units.

Solution:

In a right angle triangle,

$\tan \theta=\dfrac{Opposite}{Adjacent}$

Let $\theta$ be the missing angle. Then, for the given triangle,

$\tan \theta=\dfrac{5}{6}$

$\theta=\tan^{-1}\dfrac{5}{6}$

$\theta=39.805571^\circ$

Round the value to the nearest degree.

$\theta\approx 40^\circ$

Therefore, the measure of the required angle is 40 degrees.

8 0

2 years ago

Solve the following equations: (a) x^11=13 mod 35 (b) x^5=3 mod 64

tino4ka555 [31]

$x^{11}=13\pmod{35}\implies\begin{cases}x^{11}\equiv13\equiv3\pmod5\\x^{11}\equiv13\equiv6\pmod7\end{cases}$

By Fermat's little theorem, we have

$x^{11}\equiv (x^5)^2x\equiv x^3\equiv3\pmod5$

$x^{11}\equiv x^7x^4\equiv x^5\equiv6\pmod 7$

5 and 7 are both prime, so $\varphi(5)=4$ and $\varphi(7)=6$ . By Euler's theorem, we get

$x^4\equiv1\pmod5\implies x\equiv3^{-1}\equiv2\pmod5$

$x^6\equiv1\pmod7\impleis x\equiv6^{-1}\equiv6\pmod7$

Now we can use the Chinese remainder theorem to solve for $x$ . Start with

$x=2\cdot7+5\cdot6$

Taken mod 5, the second term vanishes and $14\equiv4\pmod5$ . Multiply by the inverse of 4 mod 5 (4), then by 2.

$x=2\cdot7\cdot4\cdot2+5\cdot6$

Taken mod 7, the first term vanishes and $30\equiv2\pmod7$ . Multiply by the inverse of 2 mod 7 (4), then by 6.

$x=2\cdot7\cdot4\cdot2+5\cdot6\cdot4\cdot6$

$\implies x\equiv832\pmod{5\cdot7}\implies\boxed{x\equiv27\pmod{35}}$

$x^5\equiv3\pmod{64}$

We have $\varphi(64)=32$ , so by Euler's theorem,

$x^{32}\equiv1\pmod{64}$

Now, raising both sides of the original congruence to the power of 6 gives

$x^{30}\equiv3^6\equiv729\equiv25\pmod{64}$

Then multiplying both sides by $x^2$ gives

$x^{32}\equiv25x^2\equiv1\pmod{64}$

so that $x^2$ is the inverse of 25 mod 64. To find this inverse, solve for $y$ in $25y\equiv1\pmod{64}$ . Using the Euclidean algorithm, we have

64 = 2*25 + 14

25 = 1*14 + 11

14 = 1*11 + 3

11 = 3*3 + 2

3 = 1*2 + 1

=> 1 = 9*64 - 23*25

so that $(-23)\cdot25\equiv1\pmod{64}\implies y=25^{-1}\equiv-23\equiv41\pmod{64}$ .

So we know

$25x^2\equiv1\pmod{64}\implies x^2\equiv41\pmod{64}$

Squaring both sides of this gives

$x^4\equiv1681\equiv17\pmod{64}$

and multiplying both sides by $x$ tells us

$x^5\equiv17x\equiv3\pmod{64}$

Use the Euclidean algorithm to solve for $x$ .

64 = 3*17 + 13

17 = 1*13 + 4

13 = 3*4 + 1

=> 1 = 4*64 - 15*17

so that $(-15)\cdot17\equiv1\pmod{64}\implies17^{-1}\equiv-15\equiv49\pmod{64}$ , and so $x\equiv147\pmod{64}\implies\boxed{x\equiv19\pmod{64}}$

5 0

3 years ago

PLS HELP WILL MARK BRAINLIEST

gavmur [86]

Answer:

1. Rolling a number less than 5

The numbers on a standard dice are 1, 2, 3, 4, 5, and 6. Therefore it is possible to roll a 6, but it is much more likely to be 1-5, simply because there are more of them.

2. Rolling a 2

Again, it is more likely that the result will be one of the other 5 numbers. But obviously a 2 is still an option, so it's not impossible.

3. Rolling a number less than 10

Every option is less than 10 so it is certain.

4 0

3 years ago

Solve the equation 36w = 16w + 24

Umnica [9.8K]

=24/20 thus the answer is 1.2

4 0

3 years ago

Read 2 more answers

Cory writes the polynomial x7 3x5 3x 1. Melissa writes the polynomial x7 5x 10. Is there a difference between the degree of the

bagirrra123 [75]

Degree of a polynomial gives the highest power of its terms. Yes there is a difference between the degrees of sum and difference of the polynomials.

<h3>What is degree of a polynomial?</h3>

Degree of a polynomial is the highest power that its terms pertain(for multi-variables, the power of term is addition of power of variables in that term).

Thus, in $x^3 + 3x^2 + 5$ , the degree of the polynomial is 3 as the highest power in its terms is 3.

(power and exponent are same thing)

<h3>What are like terms?</h3>

Those terms which have same variables raised with same powers.

For example, $x^3$ and $3x^3$ are like terms since variable is same, and it is raised to same power 3.

For example $4x^2$ and $x^3$ are not like terms as the variables are same but powers aren't same.

The given polynomials are:

$c(x) = x^7 + 3x^5 + 3x + 1\\\\p(x) = x^7 + 5x + 10$

Their sum is

$c(x) + p(x) = x^7 + 3x^5 + 3x + 1 + x^7 + 5x + 10 = (1+1)x^7 + 3x^5 + (3+5)x + 11\\\\c(x) + p(x) = 2x^7 + 3x^5 + 8x + 11$

(only like terms' coefficients can be added (or subtracted) for addition or subtraction of them )

The sum's degree is 7

Their difference is:

$c(x) - p(x) = x^7 + 3x^5 + 3x + 1 - x^7 -5x - 10 = (1-1)x^7 + 3x^5 +(3-5)x -9\\\\c(x) - p(x) = 3x^5 - 2x - 9$

Difference's degree is 5

Thus, both's degrees are not same.

Thus, Yes there is a difference between the degrees of sum and difference of the polynomials.

Learn more about subtraction of polynomials here:

brainly.com/question/9351663

4 0

2 years ago