X=3 is the awnser for this problem
Answer:
The answer for this equation would be 1
Step-by-step explanation:
Hope I helped!
Answer:
8a. x = 16√3
8b. y = 8√3
Step-by-step explanation:
8a. Determination of the value of x
Adjacent = 24
Hypothenus = x
Angle θ = 30°
The value of x can be obtained by using cosine ratio as illustrated below:
Cos θ = Adjacent /Hypothenus
Cos 30 = 24 / x
√3/2 = 24/x
Cross multiply
x × √3 = 2× 24
x × √3 = 48
Divide both side by √3
x = 48/√3
Rationalise
x = 48/√3 × √3/√3
x = 48√3 / √3 × √3
x = 48√3 / 3
x = 16√3
8b. Determination of the value of y
Opposite = y
Adjacent = 24
Angle θ = 30°
The value of y can be obtained by using Tan ratio as illustrated below:
Tan θ = Opposite / Adjacent
Tan 30 = y / 24
1 / √3 = y /24
Cross multiply
y × √3 = 1 × 24
y × √3 = 24
Divide both side by √3
y = 24 /√3
Rationalise
y = 24 /√3 × √3/√3
y = 24 ×√3 / √3 × √3
y = 24√3 / 3
y = 8√3
Answer:
The raw score for his exam grade is 99.69.
Step-by-step explanation:
Given : The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67.
To find : What is the raw score for his exam grade?
Solution :
The formula use to find the z-score is
Where, z=1.67 is the z-score
is the means
is the standard deviation
x is the raw score for his exam grade
Substitute the values,
Therefore, the raw score for his exam grade is 99.69.
In order for a function to have an inverse that is also a function there are 2 main requirements:
1. The function should be bijective (ie) the function should be one-one ( each element in codomain has not more than 1 pre image in domain) and onto ( Range should be equal to codomain)
2. The inverse function should be defined by a suitable domain and range
Hope this answer helps you..
