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jeka57 [31]
2 years ago
14

Someone please help me on this! ASAP please!! 25p

Mathematics
1 answer:
Vinil7 [7]2 years ago
7 0

Answer:

i think b

Step-by-step explanation:

yeah i think . ssnsnfhdbdhenebsjenbd

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Prior to September, 2000, taxi fares from Washington DC to Maryland were described as follows: $2.00 up to and including 1⁄2 mil
GREYUIT [131]

The piecewise function is

f(x) = 2, 0 < x ≤ 1/2

f(x) = 2 + 0.7x, x > 1/2

<h3>How to determine the piecewise function?</h3>

From the question, we have:

Fares = $2.00 ⇒ up to (and including) 1/2 miles

Fares = $0.70 increment ⇒ greater than 1/2 miles

Let x represent the number of miles, and f(x) the fares.

So, we have:

f(x) = 2, 0 < x ≤ 1/2

f(x) = 2 + 0.7x, x > 1/2

The above represents the piecewise function

Read more about piecewise function at:

brainly.com/question/18859540

#SPJ1

3 0
2 years ago
Simplify: 4x + 6(3x - 2)
gavmur [86]

Answer:

2 • (2x - 3) • (3x - 2)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
How do you write an equation for (-5,-1), (0,-1)
lesya692 [45]
Both the points have a coordinate where y is -1, so the equation is simply -1

y=-1

however if you wanted to really show the working out, it looks like this:

y=mx+c

m=change in y/change in x

m=(-1-1)/(-5+0)=0

subsitute one of the coordinates into y=mx+c

-1=0+c

c=-1

so then y=-1



4 0
3 years ago
John owns 5 health food stores in the Columbia area, and they are realizing a good profit. John decides to invest a portion of t
Nina [5.8K]

Answer:

b. $242,970.00

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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