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Dmitrij [34]
2 years ago
11

Set up equation and solve.

Mathematics
1 answer:
Liula [17]2 years ago
4 0

Answer:

Below.

Step-by-step explanation:

3x=400

x=400/3 or 133.33

2x= 266.66

Therefore, the tanks must have sizes, 133.33 and 266.66 gallons!

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8 × 10 + 6 − 2 7 + 5 × 8 − 4
riadik2000 [5.3K]

Answer:

95

Step-by-step explanation:

(8)(10)+6−27+(5)(8)−4

=80+6−27+(5)(8)−4

=86−27+(5)(8)−4

=59+(5)(8)−4

=59+40−4

=99−4

=95

hope this helped :)

6 0
2 years ago
Read 2 more answers
3 pounds of gummie bears cost $8.97. <br> What will one pound cost?
KATRIN_1 [288]

Answer:

2.99

Step-by-step explanation:

4 0
2 years ago
Find the final price of a $849.99 laptop with 6% sales tax
anygoal [31]
$900.99 (use quizlet)
4 0
3 years ago
Factor 2pq - 5qr + 10r - 4p.
Tresset [83]
The answer is B) <span>(q - 2)(2p - 5r) 

</span>2pq - 5qr + 10r - 4p = 2pq - 4p - 5qr + 10r
                                 = 2pq - 4p - (5qr - 10r)
                                 = 2p(q - 2) - 5r(q - 2)
                                 = (q - 2)(2p - 5r)
5 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α = 8 per hour, so that the number o
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Step1:

We have Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α =8 per hour, so that the number of arrivals during a time period of t hours is a Poisson rv with parameter μ = 8t

Step2:

Let “X” the number of small aircraft that arrive during time t and it follows poisson distribution parameter “”

The probability mass function of poisson distribution is given by

P(X) = , x = 0,1,2,3,...,n.

Where, μ(mean of the poisson distribution)

a).

Given that time period t = 1hr.

Then,μ = 8t

             = 8(1)

             = 8

Now,

The probability that exactly 6 small aircraft arrive during a 1-hour period is given by

P(exactly 6 small aircraft arrive during a 1-hour period) = P(X = 6)

Consider,

P(X = 6) =  

              =  

              =  

              = 0.1219.

Therefore,The probability that exactly 6 small aircraft arrive during a 1-hour period is 0.1219.

1).P(At least 6) = P(X 6)

Consider,

P(X 6) = 1 - P(X5)

                = 1 - {+++++}

                = 1 - (){+++++}

                = 1 - (0.000335){+++++}

                = 1 - (0.000335){1+8+32+85.34+170.67+273.07}

                = 1 - (0.000335){570.08}

                = 1 - 0.1909

                = 0.8090.

Therefore, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8090.

2).P(At least 10) = P(X 10)

Consider,

P(X 10) = 1 - P(X9)

                 = 1 - {+++++

5 0
3 years ago
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