I can figure out this is a frefall motion.
Starting from rest => Vo = 0
Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)
d = width of a black/clear stripe pair = 5cm = 0.05m
g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)
t =√(2*0.05m/10m/s^2) = 0.1 s
Answer: approximately 0.1 s
Likely best describes the likelihood of the probability 2/3. It is not completely certain, nor is it unlikely, and it definitely cannot be impossible.
18.5-0.5= 18
18/3= 6
So r=6
Its D, just read the graph buddy
