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3 years ago

Write down in terms of n, an expression for the nth term of the following sequences 2,8,18,32,50,

Mathematics

1 answer:

Art [367]3 years ago

4 0

Answer:

198

Step-by-step explanation:

2+6=8+10=18+14=32+18=50+22=72+26=96+30=126+34=160+38=198

You might be interested in

A baseball player hit 345 out of 1,000 balls pitched to him. What are the chances he gets a hit when he steps up to the plate?

Nimfa-mama [501]

Answer:

0.345

Step-by-step explanation:

hits/at-bats = 345/1000 = 0.345

The probability of a hit, any particular time he goes to bat. is 0.345.

The problem does not request any particular format, so 0.345 is a perfectly good answer.

In baseball, that is called a 'batting average', and is actually expressed that way - as a decimal - in a player's statistics.

On the other hand, if we did want to express the probability as a percentage, we would do this:

0.345 * 100% = (0.345 * 100) % = 34.5 %

Hope this helps

6 0

3 years ago

Find the distance between the points given. (-3, -6) and (3, 2) 4 10

DanielleElmas [232]

Answer:

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Sue and Javier are working on a statistics project to estimate the proportion of students at their school who have a pet dog. Su

JulsSmile [24]

Answer:

E) The width of Sue's interval will be narrower than Javiers

Step-by-step explanation:

In confidence intervals, as sample size increases, the width of the confidence interval decreases.

5 0

3 years ago

2. When x is -1.5 , what value of y makes the equation true

alex41 [277]

Answer:

-2

Step-by-step explanation:

y = 3x + 2.5

x = -1.5

y = 3 x -1.5 + 2.5

= -4.5 + 2.5

= -2

5 0

3 years ago

Centerville is the headquarters of Greedy Cablevision Inc. The cable company is about to expand service to two nearby towns, Spr

NeX [460]

Answer:

20.2057 Units.

Step-by-step explanation:

First, we determine the length of the cable.

Distance between Centerville (8,0) and point (x,0) is given as:

$\sqrt{(8-x)}^2=8-x$

Distance between point (x,0) and Springfield(0,7) is:

$\sqrt{(7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}$

Distance between point (x,0) and Shelvyfield(0,-7) is:

$\sqrt{(-7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}$

Therefore the Length of the Cable L(x)

$L(x)=(8-x)+2\sqrt{(7)^2+(x)^{2}}$

To find the critical point, we set the derivative of L(x)=0

$L^{'}(x)=-1+\frac{2x}{\sqrt{\left( 49 - x^{2}\right) }}$

$\frac{-\sqrt{\left( 49 - x^{2}\right)}+2x}{\sqrt{\left( 49 - x^{2}\right)}}=0\\-\sqrt{\left( 49 - x^{2}\right)}+2x=0\\\sqrt{\left( 49 - x^{2}\right)}=2x\\(\sqrt{\left( 49 - x^{2}\right)})^2=(2x)^2\\49 - x^{2}=4x^2\\49=5x^2\\x^2=\frac{49}{5}\\x= 3.1305$

To verify that L(x) has a minimum at this critical number we compute the second derivative L″(x) and find its value at the critical number.

$L^{''}(x)=\frac{\left( 98\right) \,\sqrt{\left( 49 - x^{2}\right) }}{{\left( 7 - x\right) }^{2}\,{\left( 7+x\right) }^{2}}\\At \:x=3.1305, L^{''}=0.3993$

Since $L^{''}(x)$ is positive, the minimum point of L(x) exists.

Next, we find the minimum length by substituting z=3.1305 into L(x)

$L(3.1305)=(8-3.1305)+2\sqrt{(7)^2+(3.1305)^{2}}$

Minimum Length, L=20.2057

The minimum length of the cable is 20.2057 Units.

6 0

3 years ago