The third graph represents a function.
In a function, every input (x value) has <em>exactly</em> one output (y value). If even a single input has zero or two outputs, the graph does not represent a function.
A good way of testing this is using a vertical line. As you move a vertical line from left to right across a graph, it should always be touching exactly one point on the graphed line.
In this case, every graph fails this vertical line test except for the third graph, so the third graph represents a function.
Answer:
![a=\frac{9c}{2}-b](https://tex.z-dn.net/?f=%20a%3D%5Cfrac%7B9c%7D%7B2%7D-b%20)
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
![F^{5}](https://tex.z-dn.net/?f=%20F%5E%7B5%7D%20)
Step-by-step explanation:
![F^2 \times F^3 =](https://tex.z-dn.net/?f=%20F%5E2%20%5Ctimes%20F%5E3%20%3D%20)
![= F^{2+3}](https://tex.z-dn.net/?f=%20%3D%20F%5E%7B2%2B3%7D%20)
![= F^{5}](https://tex.z-dn.net/?f=%20%3D%20F%5E%7B5%7D%20)
Answer:
x<8
Step-by-step explanation:
2x+5>3x-3
2x+8>3x
8>x
Here is the solution of the given problem above.
Given: Weight of single calf = weight of mother + 3.8%
Weight of mother = 3.75 tons or 7,500 pounds
? = weight of the calf
First, we need to find the 3.8% of 7,500 pounds. The result is 285 pounds.
So to get the weight of the calf, let's add 7,500 pounds to 285 pounds and the result is 7,785 pounds. So the weight of the calf is 7,785 pounds. Hope this helps.