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guajiro [1.7K]
3 years ago
11

Suppose that the cost of producing n pairs of shoes is given by the expression c(n)=30+5n. the average cost of producing a pair

of shoes is given by a(n)=c(n)/n. what is the derivative of the average cost function at n=10?
Mathematics
1 answer:
makkiz [27]3 years ago
7 0
<h3>Given</h3>

c(n)=30+5n\\a(n)=\dfrac{c(n)}{n}

<h3>Find</h3>

\dfrac{d}{dn}(a(n))\quad\text{at n=10}

<h3>Solution</h3>

\dfrac{d}{dn}(a(n))=\dfrac{d}{dn}\left(\dfrac{30+5n}{n}\right)=\dfrac{d}{dn}\left(30n^{-1}+5\right)\\\\=-30n^{-2}\\\\=-30\cdot 10^{-2}\qquad\text{at n=10}\\\\=-0.30

The derivative of the average cost function at n=10 is -0.30.

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Answer:

184,815

Step-by-step explanation:

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3 years ago
The scale of a model train is 1 inch to 13.5 ft. One of the cars of the model train is 5inches long. What is the length in feet
aleksklad [387]

Answer:

The length of the actual train's car is <u>67.5 feet.</u>

Step-by-step explanation:

Given:

The scale of a model train is 1 inch to 13.5 ft.

Now, to get the length of the actual car of the train.

Let the length of actual train's car be x.

And, the length of the car of model train = 5\ inches\ long.

<em>According to the scale of the model train, 1 inch is equivalent to 13.5 ft. </em>

<em>Thus, 5 inches is equivalent to </em>x.<em />

Now, to get the length of actual train's car using cross multiplication method:

\frac{1}{13.5} =\frac{5}{x}

By cross multiplying we get:

x=67.5\ feet.

Therefore, the length of the actual train's car is 67.5 feet.

7 0
3 years ago
In ΔABC, side AB is 8 units long and side BC is 25 units long. What cannot be the length of the third side
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Answer: 35

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The third side can be anywhere from 8 - 32

7 0
3 years ago
So i am dealing with equations with triangles, complimentary and supplementary, so what is 42 square + x = 180, so what is the n
Genrish500 [490]
-1584.
multiply 42 times 42 the subtract that from 180
5 0
3 years ago
How do i solve this?
Damm [24]
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