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ladessa [460]
4 years ago
12

A formula for finding the area of a rectangle is A = l • w. If you know the area (A) and width (w) of a rectangle, which formula

can you use to find the length (l)?
Mathematics
2 answers:
baherus [9]4 years ago
8 0
The formula to find the area is
A = l • w
To find the formula that can be use d to find the length I, you just divide both sides by W to get
I=A/w which is the formula that can be used to find the length

Hope it helps!



deff fn [24]4 years ago
5 0
Take the area and divide out what you know, so if you know (w) then divide (w) out from the area
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They’re similar due to AAA, each triangle is 180 degrees. since both of the triangles had a degrees of 60 i imputed 67 to the left triangle and they both equal each other
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12.
Sveta_85 [38]

Answer:

The answer is d because 10-3 is 7

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WILL MARK BRAINLIEST The following table shows the data collected from 2 random samples of 100 students from an after-school clu
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you should ask a super visor they help a lot but i think its c :)

Step-by-step explanation:

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3 years ago
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My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
A model stature is 5 in wide. If it was built with a scale of 1 in: 2 ft, then how wide is the real statue?
Gnesinka [82]

Answer:

<u>10 ft.</u>

Step-by-step explanation:

<u>Scale</u> ⇒ 1 in. : 2 ft.

  • 1 in. : 2ft. = 5 in. : x ft. [x is the width of the real statue]
  • 1/2 = 5/x
  • x = 5 × 2
  • x = <u>10 ft</u>.
8 0
2 years ago
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