Answer - yes it can
Say you have y=2x with no y intercept (b)
You can still write it as y=2x +0 or assume the y intercept (b) is zero by writing it as y=2x
Answer: I'm not sure if I'm right but i think it is A.) or maybe C.) I really don't know it could be any So please don't get mad at me if you get it wrong because of me
Step-by-step explanation:
Answer: f'(x) = 12x + 48x³ - 48x⁵
<u>Step-by-step explanation:</u>
f(x) = (1 - 2x²)³
= (1 - 2x²)(1 - 4x² + 4x⁴)
1 - 4x² + 4x⁴
<u> -2x² + 8x⁴ - 8x⁶</u>
= 1 - 6x² + 12x⁴ - 8x⁶
f'(x) = 0 -2(6)x²⁻¹ + 4(12)x⁴⁻¹ - 6(8)x⁶⁻¹
= 12x + 48x³ - 48x⁵
- 4(1/2)x - (3/7) = (1/4)
- 4(1/2)x = (1/4) + (3/7)
- (9/2)x = (7+12)/28
-(9/2)x = 19/28
x = (19/28) * 2 / 9
x = (19/14) / 9
x = 19 / (14*9)
x = 19 / 126
Answer:
- x - 24 = 0
a = 1
b = 1
c = -24
Step-by-step explanation:
(x + 4)(x - 5) = 4
x(x - 5) = - 5x
4(x - 5) = 4x - 20
- 5x + 4x - 20 = 4
- x - 20 = 4
- x - 20 - 4 = 0
- x - 24 = 0
a = 1
b = 1
c = -24
