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erica [24]
3 years ago
11

Which of the following relations is NOT a function?​

Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0

Answer:

u

Step-by-step explanation:

isjskajabaaiaboawwnkwkn

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Question 4
alex41 [277]

Answer:

Step-by-step explanation:

O

8 0
3 years ago
Expand 4p(p-7a) please solve this
Inessa05 [86]
<span>Expand 4p(p-7a) 

= 4p^2 - 28ap</span>
8 0
4 years ago
Read 2 more answers
Solve this problem by using variation of parameters method.<br> y''-y=coshx.
Gekata [30.6K]
y''-y=0\implies r^2-1=0\implies r=\pm1
\implies y_c=C_1e^x+C_2e^{-x}={C^*}_1\underbrace{\cosh x}_{y_1}+{C^*}_2\underbrace{\sinh x}_{y_2}

For the nonhomogeneous ODE

y''-y=\underbrace{\cosh x}_{f(x)}

we're looking for a particular solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\int\frac{y_2(x)f(x)}{W(y_1(x),y_2(x))}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(x)f(x)}{W(y_1(x),y_2(x))}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the two fundamental solutions.

We have

W(y_1,y_2)=\begin{vmatrix}\cosh x&\sinh x\\\sinh x&\cosh x\end{vmatrix}=\cosh^2x-\sinh^2x=1

so we're left with

u_1=-\displaystyle\int\sinh x\cosh x\,\mathrm dx=-\dfrac12\cosh^2x
u_2=\displaystyle\int\cosh^2x\,\mathrm dx=\dfrac12x+\dfrac14\sinh2x

so that the particular solution is

y_p=-\dfrac12\cosh^3x+\dfrac12x\sinh x+\dfrac14\sinh x\sinh2x
y_p=-\dfrac12\cosh x+\dfrac12x\sinh x

As y_1 already accounts for the \cosh x term in y_p, we're left with the general solution

y=C_1\cosh x+C_2\sinh x+\dfrac12x\sinh x
3 0
3 years ago
8. Caitlyn wants to build a fence around her flower garden,
ioda

Answer:

B

Step-by-step explanation:

5 0
3 years ago
On a 4 1 2 hour trip, Leslie drove 2 3 of the time. For how many hours did Leslie drive?
valentina_108 [34]

Answer:

She drove 3 hours

Step-by-step explanation:

Leslie drove 2/3 of the 4 1/2 hours trip.  To determine how long she drove, multiply these numbers together.

2/3 * 4 1/2

We need to change the second number to an improper fraction

4 1/2 = (2*4 +1)/2 = 9/2


2/3 * 9/2 = 9/3 = 3


She drove 3 hours

5 0
3 years ago
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