The hill means it was already 23 feet above ground and he went and back up so the answer is 23 positive
keeping in mind that when the logarithm base is omitted, the base 10 is assumed.
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%3D2%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D2%5Cimplies%2010%5E2%3Dx%5Cimplies%20100%3Dx)
He can make a 70 or higher to keep a B avg.
Answer:
The answer is 2
Step-by-step explanation:
Here's how I got it:
3(x - 2) = 6x - 12
Multiply 3 times x and 3 times 2, this is what you would get
3x - 6 = 6x - 12
Then, subtract the lowest x with the bigger X, this way you would have x on one side:
3x - 6 = 6x - 12
-3x -3x
This is what you should have after this:
-6 = 3x - 12
Now, to get the variable (letter that represents a number) by itself, you have to add 12 to both sides like this:
-6 = 3x - 12
+12 +12
You would get this:
6 = 3x
Finally, you have to get x by itself, so you have to divide 3 on both sides like this
6/3 = 3/3 x
That's why, your answer is 2
