Answer:
2.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
3
,
5
)
Equation Form:
x
=
3
,
y
=
5
3.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
2
,
8
)
4.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
2
,
−
3
)
Step-by-step explanation:
Step-by-step explanation:
Morning is 4 hr 15 min
afternoon is 4 hour 15 min
together is 8 hour 30 min
8.5*14 = 119 dollars
(9/18)(9/18) = 81/324. The probability that Amy takes out pink chips in both draws is 81/324.
In this example we will use the probability property P(A∩B), which means given two independent events A and B, their joint probability P(A∩B) can be expressed as the product of the individual probabilities P(A∩B) = P(A)P(B).
The total number of chips of different colors in Amy's bag is:
8 blue chips + 9 pink chips + 1 white chip = 18 color chips
Amy takes out a chip from the bag randomly without looking, she replaces the chip and then takes out another chip from the bag.
So, the probability that Amy takes out a pink chip in the first draw is:
P(A) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
Then, Amy replaces the chip an takes out another which means there are again 18 color chips divide into 8 blue chips, 9 pink chips, and 1 white chip. So, the probability of takes out a pink chip in the second draw is:
P(B) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
What is the probability that Amy takes out a pink chip in both draws?
P(A∩B) = P(A)P(B)
P(A∩B) = (9/18)(9/18) = 81/324
<u>Answer:</u>
37 minutes
<u>Step-by-step explanation:</u>
Lena has 20 dollars. 20 - 12.23 = 7.77
Lena has $7.77 dollars left.
We divide this by .21 to see how many minutes her call was.
7.77 ÷ .21 = 37
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Answer:
a = 0.64
Step-by-step explanation:
hope that helped
