Answer:
i can't solve it because it's not complete
you need something 2^2 (right here) -^1=8^x-1
Step-by-step explanation:
Answer:
q=-3 2/5
Step-by-step explanation:
First multiply -13 with (q+4)
-13q-52=7q+16
Now you have to change the order before = the numbers with q and after = the numbers without anything
-13q-7q=52+16
Remember that when you change positions the symbol too
Then solve it
-20q=68
Now u have to divide as i do
q=68/-20
you can simplify it
q=3 8/-20
Now divide by the greater divisor in this case is 4
q=3 2/-5
And organize it
q=-3 2/5
Never forget to do q=(answer)
Hopefully it helps.
The minimum value for 2x is 0
<span>the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC </span>
<span>base AB = 52 and vertical angle 2x + 34° </span>
<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
<span>(sin 34°)/30 = (sin BDC)/BC </span>
<span>is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from </span>
<span>(sin ADC)/AB = (sin BDC)/BC </span>
<span>it follows </span>
<span>(sin 2x)/22 = (sin 34°)/30 </span>
<span>sin 2x = 22 (sin 34°)/30 </span>
<span>2x = asin(22 (sin 34°)/30) ≈ 24.2° </span>
<span>x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1° </span>
<span>0 < x < 12.1°</span>
Remark
There is no short way to do this problem and no obvious way to get the answer other that to solve each part.
Solve
A
Multiply by 2
x + 1.6 = 2(x + 0.1) Remove the brackets
x + 1.6 = 2x + 0.1*2
x + 1.6 = 2x + 0.2 Subtract x from both sides
1.6 = x + 0.2 Subtract 0.2 from both sides
1.6 - 0.2 = x
1.4 = x
Circle A
B
Subtract 2x from both sides.
3x - 2x = 1.4
Circle B
C
Remove the brackets.
4x + 6 = 2x - 6 Add 6 to both sides
4x + 12 = 2x Subtract 4x from both sides.
12 = -2x Divide by - 2
12/-2 = x
x = - 6 Don't circle C
D
I'm going to be very scant in my solution of this. You can fill in the steps.
3x = 4.2
x = 4.2/3
x = 1.4
Circle D
