-2|7 - 9c| + 7 = -15 Solve for C

Work out the length of CD Answer to 3 significant figures

vladimir1956 [14]

Answer:

26

Step-by-step explanation:

I can be wrong but i most likely sure it is correct because a triangle is 180 degrees you have to add 102 with 52 take that total and subtract it with 180 to find that angle is what you need to find the length. Again i am not sure but might be right.

5 0

4 years ago

Read 2 more answers

Piper works at a camera store. He is paid an hourly rate +16% commission on everything he sells. One week, he was paid $515 for

umka21 [38]

His hourly rate is $13.75.

Let x be the hourly rate. Since he works 20 hours that week, the hourly wages are given by 20x. We add to that his commission, which is 16% of the $1500 in sales, or 0.16(1500). This totals to 515:

20x + 0.16(1500) = 515
20x + 240 = 515

Subtract 240 from both sides:
20x + 240 - 240 = 515 - 240
20x = 275

Divide both sides by 20:
20x/20 = 275/20
x = 13.75.

8 0

3 years ago

ILL BRAINLIEST YOU PLEASE HELP ME

gtnhenbr [62]

Answer:

Option C

The length of RT is 14

Step-by-step explanation:

For a given Right Triangle

m∠R = 90°, RG = 17, TG = 22

Now, By Pythagoras Theorem

(RT)² + (RG)² = (TG)²

(RT)² = (TG)² - (RG)²

(RT)² = (22)² - (17)²

(RT)² = 484 - 289

(RT)² = 195

RT = √195

RT = √195 = 13.96 = 14

Thus, The length of RT is 14

-TheUnknownScientist

4 0

3 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

3 0

3 years ago

You saved $20,000.00 and want to diversify your monies. You invest 45% in a Treasury bond for 3 years at 4.35% APR compounded an

Maru [420]

Compound Interest

A total of $20,000 is invested in different assets.

45% is invested in a Treasury bond for 3 years at 4.35 APR compounded annually.

For this investment, the principal is P = 0.45*$20,000 = $9,000.

The compounding period is yearly, thus the interest rate is:

i = 4.35 / 100 = 0.0435

The duration (in periods) is n = 3

Calculate the final value with the formula:

$M=P_{}(1+i)^n$

Substituting:

$\begin{gathered} M=\$9,000_{}(1+0.0435)^3 \\ M=\$9,000\cdot1.136259062875 \\ M=\$10,226.33 \end{gathered}$

The second investment is a CD at 3.75% APR for 3 years compounded annually. The parameters for the calculations are as follows:

P = 15% of $20,000 = $3,000

i = 3.75 / 100 = 0.0375

n = 3

Calculating:

$\begin{gathered} M=\$3,000_{}(1+0.0375)^3 \\ M=\$3,000\cdot1.116771484375 \\ M=\$3,350.31 \end{gathered}$

The third investment is in a stock plan. The initial value of the investment is

P = 20% of $20,000 = $4,000

By the end of the first year, the stock plan increased by 8%, thus its value is:

M1 = $4000 * 1.2 = $4,800

By the end of the second year, the stock plan decreased by 4$, thus the value is:

M2 = $4,800 * 0.96 = $4,608

Finally, the stock plan increases by 6%, resulting in a final balance of:

M3 = $4,608 * 1.06 = $4,884.48

Finally, the last investment is in a savings account at 2.90% APR compounded annually for 3 years (not mentioned, but assumed).

P = $20,000 - $9,000- $3,000 - $4,000 = $4,000

i = 2.90 / 100 = 0.029

n = 3

Calculating:

$\begin{gathered} M=\$4,000_{}(1+0.029)^3 \\ M=\$4,000\cdot1.089547389 \\ M=\$4,358.19 \end{gathered}$

To summarize, the final balances for each type of investment at the end of the third year are:

Investment 1; $10,226.33

Investment 2: $3,350.31

Investment 3: $4,884.48

Investment 4: $4,358.19

Total balance: $22,819.32

3 0

1 year ago

-2|7 - 9c| + 7 = -15Solve for C