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Yuri [45]
3 years ago
14

a 104 square ft room and a 130 square ft room share a wall. what is the greatest possible integer length of the shared wall

Mathematics
1 answer:
Anna11 [10]3 years ago
6 0
Since the area of a room is its length times its width, you'll need to find a common width, which will be the greatest common factor. The greatest common factor of 130 and 140 is 10. So the shared wall can at most be 10 ft. long.
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A vertical line contains the points 3,2 and 3,6 use these points and the formula for slope to explain why a vertical lines slope
Dahasolnce [82]

Answer:

see explanation

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 2) and (x₂, y₂ ) = (3, 6)

m = \frac{6-2}{3-3} = \frac{4}{0}

Since division by zero is undefined then the slope of the vertical line is undefined.

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Write the number in standard form as a decimal
pishuonlain [190]

Answer:

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Step-by-step explanation:

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7. It takes ounces of honey to make one apple pie. Betty baked 4 apple
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(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
4 years ago
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