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ElenaW [278]
3 years ago
7

Question 31 only please

Mathematics
1 answer:
Brut [27]3 years ago
3 0

Answer:

this is answer

........☺️☺️☺️☺️☺️☺️☺️

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-x/3 >5 the sign is supposed to be greater than or equal to but I don’t have that option
9966 [12]

Answer:

x ≤ -15

Step-by-step explanation:

-x / 3 ≥ 5

multiply by 3

-x ≥ 15

add x to both sides and subtract 15 from both sides

-15 ≥ x or x ≤ -15

4 0
3 years ago
Please help if you want brianleist!! :) uhm don't mind update- NO LINkS child..<br> Ty!
GrogVix [38]
12 since there are 12 x’s:)
3 0
2 years ago
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The top of a table is a parallelogram with a base of 28 cm and a height of 20 cm. Patty wants to cover the table with tiles that
suter [353]

The area of the top of the table is 28 × 20 = 560 cm2. The area of Patty’s tiles is 8 cm2 each and the area of Jake’s tiles is 9 cm2 each. Patty will need 560 ÷ 8, or 70, tiles. Jake will need 560 ÷ 9, or about 63, tiles. So, Patty will use about 7 more tiles.

3 0
3 years ago
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Bill weighs 120 lbs and is gaining ten lbs each month. Phil weighs 150 lbs and is gaining four lbs each month. How many months w
vaieri [72.5K]
First, let's write two expressions, letting x= the number of months which have elapsed:

Bill: 120 + 10x
Phil: 150 + 4x

If we set them equal to each other, then solve for x, that will be the number of months where their weights equal each other:

120+10x = 150 + 4x   [starting equation]
-120  -4x    -120 -4x    [ subtract 120 from both sides, and 4x from both sides, to isolate the term with the variable]

<u>6x</u> = <u>30</u>     [divide both sides by 5]
 5      5

x=6. They will weigh the same in six months.

5 0
3 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE. Determine m∠ABQ and determine m∠BCR.
s2008m [1.1K]

Answer:

ABQ  = 139

BCR is the same as QBC since they are alternate interior angles

BCR = 41

Step-by-step explanation:

CBQ and SCB are same side interior angles so they add to 180

2a-9  + 5a +14 = 180

Combine like terms

7a +5 = 180

Subtract 5 from each side

7a = 175

Divide by 7

7a/7 = 175/7

a = 25

ABQ  is the same as SCB  since they are corresponding angles so

ABQ = SCB = 5a+14 = 5*25+14 = 125+14 = 139

BCR is the same as QBC since they are alternate interior angles

BCR = QBC = 2a-9 = 2*25 -9 = 50-9 = 41

4 0
3 years ago
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