Question 31 only please
1 answer:
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Answer:
1) Option A: Fail to reject H0. There is insufficient evidence to support the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg.
2)Option D: The results suggest that the filters are effective
Step-by-step explanation:
We are given;
Sample size; n = 25
Sample mean; x' = 19.4 mg
Standard deviation; s = 3.52 mg
Population mean; μ = 21.1 mg
Let's state the hypotheses;
Null Hypothesis;H0: μ = 21.1 mg
Alternative Hypothesis; Ha; μ < 21.1 mg
Now, since sample size is less than 30,we will use a t-test.
Thus;
t = (x' – μ)/[s/√(n)]
t = (19.4 - 21.1)/(3.52/√25)
t = -2.415
Using an online p-value from t-score calculator as attached with the parameters t = -2.415, DF = 25 - 1 = 24, significance level = 0.05, one tailed, we have;
The p-value is 0.011885.
The calculated p-value is less than the significance level of 0.05. Thus, we will fail to reject the null hypothesis and conclude that there is insufficient evidence to support the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg.
